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maxonik [38]
3 years ago
8

Find the value of g(x)=2-x^2 and f(x)=2x-1 . f(-4)

Mathematics
2 answers:
Ivenika [448]3 years ago
6 0

Answer:

f(-4) = -9

Step-by-step explanation:

f(x)=2x-1

Let x = -4

f(-4)=2*-4-1

      = -8 -1

      = -9

Sphinxa [80]3 years ago
4 0

Solution:

f(-4) = 2(-4) - 1

f(-4) = -8 - 1

f(-4) = -9

g(-9) = 2 - (-9)^2

g(-9) = 2 - 81

g(-9) = -79

Best of Luck!

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Answer:

2328.5 weeks or 6.4 years

Step-by-step explanation:

69855/30= 2328.5/365= 6.4

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Alina says the area of the rectangular face is 10 in 2 ls
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Step-by-step explanation:

Because I randomly guessed and that was the answer.

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Simplify 8 over negative 3 divided by negative 4 over 9 . (5 points) <br> -8<br> -6<br> 6<br> 8
denpristay [2]

Answer:

6

Step-by-step explanation:

(8/3) / (-4/9)

when dividing fractions you use the acronym k.c.f (keep change flip)

keep the first fraction

change the operation (divide to multiply)

flip the other fraction

(8/-3) x (9/4)

after re-writing your expression, you want to solve

do this by multiplying both numerators by each other and same with the denominators

(-8x9) / (3x-4)

then you get a new fraction,

-72/-12

simplify,

-72/-12 = 6 (multiplying/dividing 2 negatives will always give you a positive)

3 0
3 years ago
The mass of the eggs laid by a certain breed of hen is a normally distributed random variable with mean 0.06kg and standard devi
Olin [163]

a (i) The number of standard size is 288 eggs

a (ii) The number of medium size is 1,476 eggs

a (iii) The number of large size is 36 eggs

b (i) The expected profit made from selling the standard size is Gh¢43.2

b (ii) The expected profit made from selling the medium size is Gh¢516.6

b (iii) The expected profit made from selling the large size is Gh¢16.2

The given parameters:

the mean of the distribution, m = 0.06 kg

standard deviation (std) of the distribution, d = 0.009 kg

number of the samples, n = 1800 eggs

(i) Find the position of "less than 0.052 kg (standard size)":

  • 1 standard deviation below the mean = m - d
  • m - d = 0.06 kg  -  0.009 kg = 0.051 kg

(<em>the </em><em>standard size</em><em> is 1 standard deviation below the mean</em>)

  • less than 1 standard deviation below the mean in a normal distribution is equal to 16% of the data samples
  • Number of standard size = 0.16 x 1800 = 288 eggs

(ii) Find the position of "Between 0.052 kg and 0.075kg (medium size)":

  • 0.052 kg is 1 standard deviation below the mean
  • 2 standard deviation above the mean = m + 2d
  • m + 2d = 0.06 + 2(0.009) = 0.078 kg

(<em>the </em><em>medium size</em><em> is between 1 std below the mean and 2 std above the mean</em>)

  • Between 1 std below the mean and 2 std above the mean in a normal distribution = (68 + 14)% = 82%
  • Number of medium size = 0.82 x 1800 = 1,476 eggs

(iii) Find the position of "Greater than 0.075 kg (large size)":

  • 0.078 kg is 2 standard deviation below the mean
  • greater than 2 std above the mean in a normal distribution = 2 % of the data samples
  • Number of large size = 0.02 x 1800 = 36 eggs

<u>Check:</u> <em>288 eggs + 1476 eggs + 36 eggs = 1,800 eggs</em>

(b) the cost of production of an egg = Gh¢0.45

the selling price of the standard size = Gh¢0.60

the selling price of the medium size = Gh¢0.80

the selling price of the large size = Gh¢0.95

(i) The expected profit made from selling the standard size:

Profit = total revenue - cost of production

Profit = 288(0.6) - 288(0.45) = Gh¢43.2

(ii) The expected profit made from selling the medium size:

Profit = total revenue - cost of production

Profit = 1476(0.8) - 1476(0.45) = Gh¢516.6

(iii) The expected profit made from selling the large size:

Profit = total revenue - cost of production

Profit = 36(0.9) - 36(0.45) = Gh¢16.2

Learn more here: brainly.com/question/22520030

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BigorU [14]

Answer:

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