For an individual die roll, the probability of rolling 6 is \dfrac{1}{6}
6
1
.
Effectively, this problem is asking for P(\text{1st roll is 6}\cap\text{2nd roll is 6})P(1st roll is 6∩2nd roll is 6).
Using the rule of product, this is:
\dfrac{1}{6}\times\dfrac{1}{6}=\dfrac{1}{36}
6
1
×
6
1
=
36
1
.
You are going to divide 366 by 12 you get 30.5 so 30 filled cartons
are you sure it's not 336 eggs??
Answer:
Question 1: y-11x+5 I think; Question 2: I'm not sure
Step-by-step explanation:
4(0.5n-3)=n-0.25(12-8n)
2n-12=n-3+2n
2n-12=3n-3
2n-3n=-3+12
-n=9
n = -9
