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3 years ago

14

The data set represents the number of snails that each person counted on a walk after a rainstorm. 12, 13, 22, 16, 6, 10, 13, 14

, 12
The outlier of the data set is what?

2 answers:

Pachacha [2.7K]3 years ago

8 0

The outlier of the data set is 22

hope this helps!!

shtirl [24]3 years ago

5 0

22 is the outlier of the set.<span />

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Find the value of k

Readme [11.4K]

Answer:

12

Step-by-step explanation:

A straight line is equal to 180. The line AB is 180 degrees. This means 174 + angle = 180 for the angle between point D and B. It must be 6 degrees. This is the same angle as the angle between point A and C.

Line CD is also straight and equal to 180. On the line are the angles, 4k + 90 + 3k + 6 = 180. Solve for k by combining like terms and then using inverse oeprations.

4k + 90 + 3k + 6 = 180

7k + 96 = 180

7k = 84

k = 12

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2 years ago

What THERE numbers below, when added together, total the highest possible score? 47629658

miv72 [106K]

The answer might be 7,8,9

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3 years ago

Precal help if you could could you answer both. Me finishing this helps me graduate.

oee [108]

Exercise 1:

The easiest way to compute powers of complex numbers is to write them in the form

$z = \rho e^{i\theta} = \rho(\cos(\theta)+i\sin(\theta))$

In this form, you have

$z^n = \rho^n e^{in\theta} = \rho^n(\cos(n\theta)+i\sin(n\theta))$

The magnitude of the number is given by

$z=a+bi \implies \rho = \sqrt{a^2+b^2}$

So, we have

$z=-1+\sqrt{3}i \implies \rho = \sqrt{1+3}=2$

As for the angle, we have

$z=a+bi \implies \theta = \text{atan2}\dfrac{b}{a}$

So, we have

$z=-1+\sqrt{3}i \implies \theta = \text{atan2}\left(\dfrac{-\sqrt{3}}{-1}\right) = -\dfrac{2\pi}{3}$

Finally,

$z=-1-\sqrt{3}i = 2\left(\cos\left( -\dfrac{2\pi}{3}\right) + i\sin\left( -\dfrac{2\pi}{3}\right)\right) \implies z^6 = 2^6\left(\cos\left( -4\pi\right) + i\sin\left(-4\pi\right)\right) = 64$

Exercise 2:

You simply have to compute the trigonometric function:

$\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2},\quad \sin\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}$

So, we have

$z = \sqrt{2}\left(\dfrac{\sqrt{2}}{2} - i\dfrac{\sqrt{2}}{2}\right) = 1-i$

7 0

2 years ago

SOMEONE PLEASE HELP ME ASAP PLEASE!!!!

ehidna [41]

Answer:

Therefore,

$a_{21}=2$

Step-by-step explanation:

Given:

$A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]$

To Find:

a₂₁ = ?

Solution:

Let,

$A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right]$

We require ' a₂₁ ' i.e Second Row First Column Element

So on Comparing we get

∴ $a_{21}=2$

Therefore,

$a_{21}=2$

5 0

2 years ago

Whats 500000 x 700=

Alexxandr [17]

Answer:

PERIOD

Step-by-step explanation:

4 0

3 years ago