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DENIUS [597]
3 years ago
11

A cylinder has a diameter of 6 ft and height of 9 ft. What is the volume of this cylinder? A) 54 ft2 B) 169.8 ft3 C) 254.3 ft3 D

) 1,017 ft3
Mathematics
2 answers:
Margarita [4]3 years ago
7 0
<span>In order to find the volume of a cylinder, we must find the area of its circular face and multiply that value by its height. The area of a circle is (pi)*r^2. The diameter is twice the radius, so the cylinder has a radius of 6/2, or 3 ft. The area of the circular face of the cylinder is therefore 9(pi) or approximately 28.27 sq. ft. Multiplying that area by the height of 9 ft. results in a volume of approximately 254.3 cubic ft., which is answer C.</span>
Alexeev081 [22]3 years ago
7 0
C) 254.3

1. 3.14 * 3^2  
2. 28.26 * 9
3. 254.3
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2ones is the same as 20 tenth.Explain
babymother [125]
How did you get that as an answer ?
3 0
3 years ago
What are the factors of 252 .
Naya [18.7K]

Answer:

252 is a composite number.

Prime factorization: 252 = 2 x 2 x 3 x 3 x 7, which can be written 252 = (2^2) x (3^2) x 7

The exponents in the prime factorization are 2, 2, and 1. Adding one to each and multiplying we get (2 + 1)(2 + 1)(1 + 1) = 3 x 3 x 2 = 18. Therefore 252 has 18 factors.

Factors of 252: 1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, 126, 252

Factor pairs: 252 = 1 x 252, 2 x 126, 3 x 84, 4 x 63, 6 x 42, 7 x 36, 9 x 28, 12 x 21, or 14 x 18

Taking the factor pair with the largest square number factor, we get √252 = (√7)(√36) = 6√7 ≈ 15.875

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please how to answer.
vivado [14]

Answer:

Blue Rectangle: <u>135 mm²</u>

Blue Triangle: <u>45 mm²</u>

<em>Not sure if you need this but the </em>Total Square: <u>225 mm²</u>

Step-by-step explanation:

Area of a rectangle: <u>length x width</u>

Area of a triangle: \frac{1}{2}<u> x base x height</u>

First find the area of the blue rectangle.

Length = 15 mm

Width = 9 mm

Area = 135 mm²

Now find the area of the blue triangle:

Base = 6 mm (because the bottom is 15 total and you subtract the 9)

Height = 15 mm

Area = 45 mm²

Hope it helps!

6 0
1 year ago
Find the integral <br> ∫√(9+x)/(9-x)
densk [106]

I suppose you mean

\displaystyle \int \frac{\sqrt{9+x}}{9-x} \, dx

Substitute y = √(9 + x). Solving for x gives x = y² - 9, so that 9 - x = 18 - y², and we have differential dx = 2y dy. Replacing everything in the integral gives

\displaystyle \int \frac{2y^2}{18 - y^2} \, dy

Simplify the integrand by dividing:

\dfrac{2y^2}{18 - y^2} = -2 + \dfrac{36}{18 - y^2}

\implies \displaystyle \int \left(\frac{36}{18-y^2} - 2\right) \, dy

For the first term of this new integral, we have the partial fraction expansion

\dfrac1{18 - y^2} = \dfrac1{\sqrt{72}} \left(\dfrac1{\sqrt{18}-y} + \dfrac1{\sqrt{18}+y}\right)

\implies \displaystyle \frac{36}{\sqrt{72}} \int \left(\frac1{\sqrt{18}-y} + \frac1{\sqrt{18}+y}\right) \, dy - 2 \int dy

The rest is trivial:

\displaystyle \sqrt{18} \int \left(\frac1{\sqrt{18}-y} + \frac1{\sqrt{18}+y}\right) \, dy - 2 \int dy

= \displaystyle \sqrt{18} \left(\ln\left|\sqrt{18}+y\right| - \ln\left|\sqrt{18}-y\right|\right) - 2y + C

= \displaystyle \sqrt{18} \ln\left|\frac{\sqrt{18}+y}{\sqrt{18}-y}\right| - 2y + C

= \boxed{\displaystyle \sqrt{18} \ln\left|\frac{\sqrt{18}+\sqrt{9+x}}{\sqrt{18}-\sqrt{9+x}}\right| - 2\sqrt{9+x} + C}

6 0
2 years ago
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