What don't you get about the problem ?
Answer:
-√(1 - 2x) + C
Step-by-step explanation:
1/√(1-2x)
We want to integrate it. Thus;
∫1/√(1 - 2x) dx
Let u = 1 - 2x
Thus;
du/dx = -2
Thus, dx = -½du
Thus,we now have;
-½∫1/√(u) du
By application of power rule, we will now have;
-½∫1/√(u) du = -√(u) + C
Plugging in the value of u, we will have;
-√(1 - 2x) + C
63/9 + 40 - 35/7 =
7 + 40 - 5 =
47 - 5 =
42 <==
a = 2x - 18
remove the parenthesis and simplify
x - 3 + x - a = 15
2x - 3 - a = 18 ( add 3 to both sides
2x - a = 18 ( subtract 2x from both sides )
- a = 18 - 2x ( multiply through by - 1 )
a = - 18 + 2x
a = 2x - 18