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kicyunya [14]
3 years ago
7

Can the following question be considered a statistical question, and why? For how many hours does each student at Bryan Middle S

chool sleep?
Yes, it specifies the population
No, it does not specify the population
Yes, it anticipates enough variability in responses
No, it does not anticipate enough variability in responses
Mathematics
1 answer:
faltersainse [42]3 years ago
7 0

Answer:

<h2>Yes, it anticipates enough variability in responses</h2>

Step-by-step explanation:

The given question is

<em>"How many hours does each student at Bryan Middle School sleep?"</em>

<em />

This is an actual statistical question, because it's aimed to measure a variable: hours of sleep.

An important characteristic of a statistical question is that you get a range of answers, you have variability, which enables you to create distributions of that data set.

Therefore, the right answer is "Yes, it anticipates enough variability in responses".

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Factor the following polynomial completely.
stiv31 [10]

Answer:

10x^2 (x+2) (x+6)

Step-by-step explanation:

assuming you meant 120 not 1120

10x^4+ 80x^3 + 120x^2

factor out 10 x^2

10x^2 (x^2 +8x+12)

what numbers multiply together to get 12 and add together to get 8

2*6 = 12   2+6 = 8

10x^2 (x+2) (x+6)

B and D are the same answer?????

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3 years ago
A group of college students are asked: "Including elementary, middle school, high school, trade school, and college, how many sc
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In a histogram, the highest bar is the mode, which means the number the bar represents appears the most.


The answer would be D. Three, because it appears most often.


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3 years ago
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,Suppose that 80\%, percent of trees in a forest of 300 trees are infected with a virus, and we take an SRS of 5 trees to test f
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Answer: .0512

Step-by-step explanation:

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3 years ago
ramone has 5 difficult questions left to answer on a multiple choice test. Each question has 3 choices. For the first 2 of these
olchik [2.2K]
1. a b c
2. a b c
3. a b c
4. a b c
5. a b c

then she eliminated 1 choice in 1 and 2, say as follows

1.    b c
2. a b 
3. a b c
4. a b c
5. a b c

Probability of answering correctly the first 2, and at least 2 or the remaining 3 is 
P(answering 1,2 and exactly 2 of 3.4.or 5.)+P(answering 1,2 and also 3,4,5 )

P(answering 1,2 and exactly 2 of 3.4.or 5.)=
P(1,2,3,4 correct, 5 wrong)+P(1,2,3,5 correct, 4 wrong)+P(1,2,4,5 correct, 3 wrong)
also P(1,2,3,4 c, 5w)=P(1,2,3,5 c 4w)=P(1,2,4,5 c 3w )
so  
P(answering 1,2 and exactly 2 of 3.4.or 5.)=3*P(1,2,3,4)=3*1/2*1/2*1/3*1/3*2/3=1/4*2/9=2/36=1/18

note: P(1 correct)=1/2
         P(2 correct)=1/2
         P(3 correct)=1/3
         P(4 correct)=1/3
         P(5 wrong) = 2/3

P(answering 1,2 and also 3,4,5 )=1/2*1/2*1/3*1/3*1/3=1/108

Ans: P= 1/18+1/108=(6+1)/108=7/108
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4 years ago
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Answer:

(9,6)

Step-by-step explanation:

(6,9)

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3 years ago
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