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Answer:
- The smallest area the field could be is 6,400 m²
- The largest area the field could be is 8,250 m²
Step-by-step explanation:
Given;
smallest possible length of the international soccer field, L₀ = 100 m
smallest possible breadth of the international soccer field, B₀ = 64 m
Largest possible length of the international soccer field, L₁ = 110 m
Largest possible breadth of the international soccer field, B₁ = 75 m
Area of a rectangle is given by;
A = L x B
The smallest area the field could be is calculated as;
A₀ = L₀ x B₀
A₀ = 100 m x 64 m
A₀ = 6,400 m²
The largest area the field could be is calculated as;
A₁ = L₁ x B₁
A₁ = 110 m x 75 m
A₁ = 8,250 m²
The answer is X=18 for this 2 step equation
Answer:
PE = 102.9 Joules
Step-by-step explanation:
PE = mgh
= (7.0 kg)(9.8 m/s^2)(1.5 m)
= 102.9 Joules
Answer:
-36+7x
Step-by-step explanation:
