Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
2014⇒2277 athletes
2013⇒2070 athletes.
x=number of athletes in 2013
110% of x=2277
(110/100x=2277
x=(2277*100)/110=2070
2012⇒2300 athletes.
x=number of athletes in 2012
90% of x=2070
(90/100)x=2070
x=(2070*100)/90=2300
Answer: 2300 athletes were signed up for a spring sport in 2012.
Answer: Try 21
Step-by-step explanation:
Answer:
3x^4-6x^3+8x^2-16x-59/x+2
Step-by-step explanation:
Answer: 96 cubes could fit
Step-by-step explanation:
4x4x3=48
48x2=96