What grade is that is that 4th or 5th grade
sqrt(81) = 9
sqrt(100) = 100
sqrt(92) is between 9 and 10.
Answer: 10
Answer:
x = 147/5 and y = 78
Step-by-step explanation:
First solve by substitution and put 78 into y in -5x + 2y = 9 so you get 147/5
then plug 147/5 into x and find y
Given:
3, -2
1, 2
-1, -4
-1, 2
The format is (x,y)
The domain is all the x-values while range is all the y-values.
domain: (3,1, -1,-1) 2nd option given.
Answer:
452.39 units^2
Step-by-step explanation:
formula: 
