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3 years ago

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Mathematics

1 answer:

exis [7]3 years ago

4 0

Answer:

Note Due Date Interest due at Maturity

1 Mar 6 $500

2 Apr 23 $360

3 July 20 $840

4 Sept 6 $945

5 Nov 29 $270

6 Dec 30 $300

Step-by-step explanation:

Calculation to Determine the due date and the amount of interest due at maturity for Flush Mate Co.

Using this formula to Calculate for the amount of interest due at maturity.

Interest due at Maturity= [Face amount * Numbers of days to maturity / 360 * Interest rate]

Note, Due Date, Face Amount, No of days to maturity, Interest rate, Interest due at Maturity

1 Mar 6 80,000× 45/360 ×5% =$500

2 Apr 23 24,000 × 60/360 ×9% =$360

3 July 20 42,000×120/360 ×6% =$840

4 Sept 6 54,000× 90/360 ×7% =$945

5 Nov 29 27,000× 60/360 ×6% =$270

6 Dec 30 72,000× 30/360 ×5% =$300

Therefore the due date and the amount of interest due at maturity for Flush Mate Co are:

Note Due Date Interest due at Maturity

1 Mar 6 $500

2 Apr 23 $360

3 July 20 $840

4 Sept 6 $945

5 Nov 29 $270

6 Dec 30 $300

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Answer:

(8, -9), (11, -9)

Step-by-step explanation:

The points (5, 7) and (7, 7) are on a horizontal line in which the y-coordinates of all points are 7. The line has equation y = 7.

For a line to not intersect the line y = 7, it must be parallel to y = 7.

The answer is the pair of points which both have the same y-coordinate, and that y-coordinate is not 7.

From the choices you added to your comments, the only choice with two points with the same y-coordinate is (8, -9) and (11, -9). This is the answer.

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3 years ago

A certain plant runs three shifts per day. Of all the items produced by the plant, 50% of them are produced on the first shift,

Snezhnost [94]

Answer:

0.2941 = 29.41% probability that it was manufactured during the first shift.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: Manufactured during the first shift.

Probability of a defective item:

1% of 50%(first shift)

2% of 30%(second shift)

3% of 20%(third shift).

$P(A) = 0.01*0.5 + 0.02*0.3 + 0.03*0.2 = 0.017$

Probability of a defective item being produced on the first shift:

1% of 50%. So

$P(A \cap B) = 0.01*0.5 = 0.005$

What is the probability that it was manufactured during the first shift?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.005}{0.017} = 0.2941$

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Answer:

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Step-by-step explanation:

This is a permutation, not a combination, because order matters.

Here's why:

Arbitrarily, let's say that the three students chosen for the award are Abby, Bob, and Charlie. The order of which each award is given to the three of them matters, because otherwise they would be receiving different awards. For example, if Abby gets the research award, Bob gets the teaching award, and Charlie gets the service award, this would be notably different than if Abby got the teaching award, Bob got the service award, and Charlie got the research award.

Therefore, for the first award, we have 25 people to choose from. After we select that person, we have 24 people to choose from, since the problem stipulates that each student can receive at most one award. Then 23, and so on.

Since we're choosing three people to give awards to, there are:

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