Answer:
The solution of system of equation is (-2,0)
Step-by-step explanation:
Given system of equation are
Equation 1 : 2x+y=(-4)
Equation 2 : y+
x=(-1)
To plot the equation of line, we need at least two points
For Equation 1 : 2x+y=(-4)
Let x=0
2x+y=(-4)
2(0)+y=(-4)
y=(-4)
Let x=1
2x+y=(-4)
2(1)+y=(-4)
y=(-6)
Therefore,
The required points for equation is (0,-4) and (1,-6)
For Equation 2 : y+x=(-1)
Let x=0
y+x=(-1)
y+(0)=(-1)
y=(-1)
Let x=2
y+x=(-1)
y+(2)=(-1)
y=(-2)
The required points for equation is (0,-1) and (2,-2)
Now, plot the graph using this points
From the graph,
The red line is equation 1 and blue line is equation 2
Since. The point of intersection is solution of system of equations
The solution of system of equation is (-2,0)
Both graphs x =4 and y =4 will be perpendicular to each other.
- The graph of x = 4 is a vertical line down the Graph scope
- The graph of y =4 is a horizontal line side the Graph scope.
Both the Lines will meet exactly at ( 4, 4 ) perpendicularly at each other both of them intersecting at 90 degrees.
Vertical and Horizontal lines are perpendicular to each other (90 Degrees).
Know more about Perpendicular Lines: brainly.com/question/1202004
If
then the derivative is
Critical points occur where 
. This happens for
In the first case, we find
In the second,
So all the critical points occur at multiples of 
, or 
. (This includes all the even multiples of .)
Answer:
what is it that you are looking for tho
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
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