Question

2 KClO_2 produces 2 KCl+ 3O_2 when heated. If this reaction produces 82.8 g of KCl how many grams of O2 were produced?

Answer 1

Answer:

37.046 grams of oxygen gas were produced.

Explanation:

$2KClO_2\rightarrow 2KCl+ 3O_2$

Moles of potassium chlorite = $\frac{82.2 g}{106.5 g/mol}=0.7718 mol$

According to reaction 2 moles of potassium chlorite gives 3 moles of oxygen gas.

Then 0.7718 moles of potassium chlorite will give:

$\frac{3}{2}\times 0.7718 mol=1.1577 mol$ of oxygen gas.

Mass of 1.1577 moles of oxygen gas:

1.1577 mol × 32 g/mol = 37.046 g

37.046 grams of oxygen gas were produced.