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Anastaziya [24]
3 years ago
12

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq

uation P V = C , where C is a constant. Suppose that at a certain instant the volume is 500 cm 3 , the pressure is 200 kPa , and the pressure is increasing at a rate of 30 kPa/min . At what rate is the volume decreasing at this instant?
Chemistry
1 answer:
ad-work [718]3 years ago
5 0

Answer:

-75 cm^3/min

Explanation:

Given from Boyle's law;

PV=C

From product rule;

VdP/dt + PdV/dt = dC/dt

but dC/dt = 0, V= 500 cm^3, P= 200kPa, dP= 30kPa/min

PdV/dt = dC/dt - VdP/dt

dV/dt = dC/dt - VdP/dt/ P

substituting values;

dV/dt = 0 - (500 * 30)/200

dV/dt = -75 cm^3/min

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Answer:

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Explanation:

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3 years ago
Which of the following will have the slowest rate of diffusion at a given temperature?
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<h3>Answer:</h3>

Chlorine gas (Cl₂)

<h3>Explanation:</h3>
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In this case we are given gases, CI₂

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Looking at the molar mass of the gases given;

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Endothermic reactions are those in which heat is absorbed by the system from the surroundings and exothermic reactions are those in which heat is released by the system to the surroundings. \Delta H  for Endothermic reaction is positive and  

As on dissolution of salt, the temperature of water increases, the heat has been released from system into surroundings and thus \Delta H is negative.

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