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Anastaziya [24]
3 years ago
12

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq

uation P V = C , where C is a constant. Suppose that at a certain instant the volume is 500 cm 3 , the pressure is 200 kPa , and the pressure is increasing at a rate of 30 kPa/min . At what rate is the volume decreasing at this instant?
Chemistry
1 answer:
ad-work [718]3 years ago
5 0

Answer:

-75 cm^3/min

Explanation:

Given from Boyle's law;

PV=C

From product rule;

VdP/dt + PdV/dt = dC/dt

but dC/dt = 0, V= 500 cm^3, P= 200kPa, dP= 30kPa/min

PdV/dt = dC/dt - VdP/dt

dV/dt = dC/dt - VdP/dt/ P

substituting values;

dV/dt = 0 - (500 * 30)/200

dV/dt = -75 cm^3/min

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A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X ​
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\LARGE{ \boxed{  \rm{ \red{Required \: answer}}}}

☃️ Chemical formulae ➝ \sf{CaCO_3}

<h3><u>How to find?</u></h3>

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

\boxed{ \sf{No. \: of \: moles =  \frac{given \: weight}{molecular \: weight} }}

<h3><u>Solution:</u></h3>

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⇛ No. of moles = 0.1 moles

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<u>━━━━━━━━━━━━━━━━━━━━</u>

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Explanation:

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