Answer:
The correct answer is 29 grams.
Explanation:
Based on the given question, the reaction will be,
CH3CH=CHCH3 + H2 ⇒ CH3CH2CH2CH3
The molecular weight of butene is 56 grams per mole, and the molecular weight of butane is 58 grams per mole.
Thus, it can be said that 56 grams of butene reacts with hydrogen gas and produces 58 grams of butane.
Therefore, 28 grams of butene when reacts with hydrogen gas to give,
= 58/56 * 28 = 29 grams of butane.
Hence, the mass of butane produced will be 29 grams.
Answer: I would go with B
Explanation: The motor in a circuit isn't moving. That's very vague, but it doesn't show any evidence that an electrical current is going through it, likewise it doesn't show that an electrical current ISN'T going through it. However in regards to this question I would go with B.
The theoretical proportion is given by the balanced chemical equation:
2 mol NBr / 3 mol Na OH
Then x mol NaOH / 40 mol NBr3 = 3mol NaOH/2 mol NBr3
Solve for x, x = 40 * 3/2 = 60 mol NaOH.
Given that there are 48 mol NaOH (less than 60) this is the limitant reactant and the other is the excess reactant.
Answer: NBr3..
Because the ring is hollow
<u>Answer:</u> The rate law expression for the given reaction is written below.
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:
Rate law expression for the reaction:
![\text{Rate}=k[NO]^2[H_2]^2](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BH_2%5D%5E2)
Hence, the rate law expression for the given reaction is written above.
