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4 years ago

F(x)= -5x+9 ; reflection in the y-axis a.g(x)=5x-9 b.g(x)=5x+9 c.g(x)=9x-5 d.g(x)=5x-5

Mathematics

1 answer:

Sunny_sXe [5.5K]4 years ago

7 0

<h3>Answer: g(x) = 5x+9, second choice</h3>

Explanation:

When we reflect over the vertical y axis, every negative x value becomes positive and vice versa. So we effectively replace x with -x like so

f(x) = -5x+9

f(-x) = -5(-x)+9 ... replace every x with -x

f(-x) = 5x+9

g(x) = 5x+9

A point like (1,4) on f(x) will reflect over to (-1,4) on g(x). If we apply this to every point on f(x), then all of f(x) will reflect to g(x).

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Factor:<br><br><br>(m+2)^2−(m+2)+mn·(n+2)+2n(n+2)

bazaltina [42]

ANSWER
${(m + 2)}( {n}^{2} + 2n + m + 1)$

EXPLANATION

The given expression is

${(m + 2)}^{2} - (m + 2) + mn(n + 2) + 2n(n + 2)$

We factor to get,

$= {(m + 2)}(m + 2 - 1) +n (n + 2) (m+ 2)$

This implies that,

$= {(m + 2)}(m + 1) +n (n + 2) (m+ 2)$

We factor further to obtain,

$= {(m + 2)}((m + 1) +n (n + 2))$

or

$= {(m + 2)}( {n}^{2} + 2n + m + 1)$

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3 years ago

The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor

nadya68 [22]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can use as an estimator for p $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

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3 years ago

What is the probability of pulling a card that is not an odd numbered card from a deck of cards?

leva [86]

Total number of cards = 52
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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