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2 years ago

8

For every 10 cans John collected for recycling, he earned 9 cents. After he collects 80 cans, how much money would he have earne

d?

1 answer:

andre [41]2 years ago

5 0

Answer:

72 cents

Step-by-step explanation:

10(1) = 9 cans so 80(8) = 72 cans.

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Factor the expression over the complex numbers. x3+20x−4x2−80

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Answer: (x^2+20)(x-4)

Step-by-step explanation:

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2 years ago

4x+2y=4 put in slope intercept form. Complete table for x and y<br>

musickatia [10]

Hi there! Putting this equation into a slope-intercept basically means solving for y. Move everything besides the constant of y and y to the other side giving you 2y=-4x+4. Divide both sides by 2 to give you y alone. This gives you y=-2x+2
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2 years ago

Dennis is cutting construction paper into rectangles for a project he needs to cut one rectangle that is 12 inches times 15 1/4

Nataly_w [17]

Answer:

Dennis need 288.91 square inches of construction paper for his project.

Step-by-step explanation:

Dennis is cutting construction paper into rectangles for a project.

He needs to cut one rectangle that is 12 inches times 15 1/4 inches

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$15\frac{1}{4} = \frac{(15\times4) + 1}{4} = \frac{61}{4}$

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He needs to cut another rectangle that is 10 1/3"" x 10 1/4""

The symbol " means inches

First convert the mixed fraction to improper fraction

$10\frac{1}{3} = \frac{(10\times3) + 1}{3} = \frac{31}{3}$

$10\frac{1}{4} = \frac{(10\times4) + 1}{4} = \frac{41}{4}$

So the area of 2nd rectangle is

$A_2 = \frac{31}{3}\times \frac{41}{4} = 105.91 \: in^{2}$

The total construction paper needed for this project is

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Therefore, Dennis need 288.91 square inches of construction paper for his project.

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3 years ago

The graph of a sinusoidal function has a minimum point at (0,3)(0,3)left parenthesis, 0, comma, 3, right parenthesis and then in

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Answer:

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Step-by-step explanation:

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1 year ago

The diameter of Circle Q terminates on the circumference of the circle at (3,0) and (3,-7) . Write the equation of the circle in

Deffense [45]

Step-by-step explanation:

The center of a circle with 2 end points of a di diameter is the midpoint of the two endpoints.

The formula needed to find the minpoints is

(x,y) = (x2 + x1)/2, (y2 + y1)/2

x2 = 3

x1 = 3

y2 = 0

y1 = -7

midpoint = (3 + 3)/2, (0 - 7)/2

midp[oint = 3,-3.5

The midpoint is the center of the circle. Observe that the signs get changed when entering the values for (x,y)

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To determine r^2 you need only take the distance from the center to oneof the endpoints.

r^2 = (3 - 3)^2 + (3.5 - 0)^2

r^2 = 3.5^2

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2 years ago