Question

Which equation describes a line having a slope of -3/4 and a y-intercept of 5/2?

Answer 1

Answer:

the answer is c most likely

Step-by-step explanation:

Answer 2

Answer:

C. 3x + 4y = 10

Step-by-step explanation:

We shall change all the equation to the slope-intercept form, to get their slope and intercept.

To do the above, we will change it to the form y=mx + c

option A

4x + 3y = -10

subtract 4x from both-side of the equation

4x-4x + 3y = -4x - 10

3y = -4x - 10

Divide through the equation by 3

y = -4/3 x - 10/3

comparing the above equation with y=mx + c

The slope(m) is -4/3 and the  intercept(c)  is -10/3

OPTION B

4x + 3y = 10

Its almost the same with option A, except with the fact that the 10 is having a positive sign. This implies that its slope m = -4/3 and intercept(c) =10/3

OPTION C

3x + 4y = 10

Subtract 3x frrom both-side of the equation

3x - 3x + 4y =-3x + 10

4y = -3x + 10

Divide through the  equation by 4

4y/4 = -3x /4  + 10/4

y = -3/4x + 5/2

Comparing the above equation by y=mx + c

The slope (m) =-3/4   and the intercept(c) =5/2

Therefore the equation which describe a line having a slope of -3/4 and y-intercept 5/2  is  3x + 4y = 10