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3 years ago

53-_ =30 find missing number

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

8 0

23 is the missing number

Alex787 [66]3 years ago

6 0

The correct answer is 23. Subtract 30 from 53, then check you answer by plugging in 23 in the equation and solving. Since it comes out to be 30, you know you are correct.

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Please show your work!!

jarptica [38.1K]

Answer:OK ILL HELP

Step-by-step explanation:Combine

and

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2 years ago

in a recent year one United States dollar was equal to about 82 Japanese yen how many Japanese yen are equal to $1,00 $1,000 $10

Yuki888 [10]

In a recent year, one United States dollar was equal to about 82 Japanese. How many Japanese yen are equal $100?$1,000?$10,000
Given is: 

1 USD = 82 Japanese Yen 

Conversion: 

1. 100 USD x 82 JY / 1 USD = 8, 200 Japanese Yen 
2. 1000 USD x 82 JY / 1 USD = 82, 000 Japanese Yen 
3. 10, 000 USD x 82 JY / 1 USD = 820, 000 Japanese Yen

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3 years ago

During the walk-a-thon, brian walks 3 and one fourth kilometers, and Stacy walks 2 and seven eighths kilometers. How many more k

BARSIC [14]

Answer:

3/8 or three eighths

8 0

3 years ago

Solve using the box method

Lena [83]

$\huge\text{Hey there!}$

$\large\text{Just SIMPLIFY the given EQUATION or find the DIFFERENCE}\\\large\text{OF the SQUARES... Here is the formula: }\mathsf{\bf a^2 - b^2 =(a+b)(a-b)}$

$\large\text{Equation: }\mathsf{\dfrac{(4x^2-9)}{(2x + 3)}}$

$\large\text{Rewrite }\mathsf{ 4x^9 - 9}\large\text{ in the formation of }\mathsf{a^2 - b^2}\large\text{ whereas}\mathsf{a = 2x \ \&\ b = 3.}$

$\large\text{Equation: }\mathsf{\dfrac{(2x)^2-3^2}{2x + 3}}$

$\large\text{This is where you try to do the DIFFERENCE OF its SQUARES}$

$\mathsf{\dfrac{(2x + 3)(2x - 3)}{2x + 3}}$

$\large\text{CANCEL out: }\mathsf{(2x + 3)\ - (2x +3)}\large\text{ because it gives you 0}$

$\large\text{This leaves us with }\mathsf{\bf 2x - 3}\large\text{ as your POSSIBLE ANSWER}$

$\boxed{\boxed{\large\text{Answer: \huge \bf 2x - 3}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

$\large\text{Note: There is/are many ways to solve for equations like this.... this was just}\\\large\text{the quickest and easiest way to understand it!}$

3 0

3 years ago

a vertical pole 10 ft. tall casts a 14-foot shadow. what is the angle of elevation of the sun to the nearest degree?

PtichkaEL [24]

Draw a right triangle.

$tan(theta) = \frac{opposite}{adjacent}$

$tan(theta) = \frac{10}{14}$

Arctangent (tan^-1) can be used to find theta.

$tan^{-1}(\frac{10}{14})=theta$

$theta\ is\ approx\ \boxed{36\ degrees}$

8 0

3 years ago