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steposvetlana [31]
3 years ago
6

write the equation of a line in slope intercept form that is perpendicular to the line y = –4x and passes through the point (2,

6).
Mathematics
1 answer:
Neko [114]3 years ago
5 0
For perpendicular lines, m1m2 = -1 or m2 = -1/m1
Line y = -4x has a slope of -4, hence, required slope is -1/-4 = 1/4
Required equation is y - 6 = 1/4(x - 2)
y - 6 = 1/4x - 1/2
y = 1/4x - 1/2 + 6
y = 1/4x + 11/2
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Answer:

Following are the solution to this question:

Step-by-step explanation:

Using formula:

\text{Simple Interest} = \frac{P \times R \times T}{100} \\\\\text{ Total amount} = \text{principle}+  \text{Simple Interest}

In question (1):

Principle= \$ 600\\Rate = \ 8 \%\\Time= \ 5

In point a:

\to \frac{P \times R \times T}{100} \\\\\to \frac{(600 \times  8 \times 5)}{100}\\\\ \to  240

In point b:

\to amount = principle \ +\ simple \ interest

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In question (2):

Principle= \$ 12,450\\Rate = \ 7.25 \%\\Time= \ 6

In point a:

\to \frac{P \times R \times T}{100} \\\\\to \frac{(12,450 \times  7.25 \times 6)}{100}\\\\ \to  5,415.75

In point b:

\to amount = principle \ +\ simple \ interest

                 = 12,450 + 5,415.75 \\\\= 17,865.75

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