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oksian1 [2.3K]
3 years ago
12

Complete the recursive formula f(1) = f(n) = f(n − 1)

Mathematics
1 answer:
Anarel [89]3 years ago
3 0

Answer:

Step-by-step explanation:

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PLS HELP FOR 60 POINTSS PLSS IF U HELP ILL SEND 30 MORE POINTSS
Mariulka [41]

Answer:

1.  42/x

2.  14 students

Step-by-step explanation:

1.  42 divided by x

    x=students on trip last year

2. 42 divided by 3

    42/3=14 students this year

 

3 0
3 years ago
Help....!! I need to solve this simultaneous equation y=x-2 and y=3x+5 With working out if possible please....
Blababa [14]

Step-by-step explanation:

Y= x - 2. Y = 3x + 5

Putting value of y

x - 2 = 3x + 5

-2 - 5 = 3x - x

-7 = 2x

-7/2 = x

Putting value of x

Y = 3(-7/2) + 5

Y = - 10.5 + 5

Y = - 5.5

6 0
3 years ago
A simple random sample from a population with a normal distribution of 98 body temperatures has x =98.90 °F and s =0.68°F. Const
Ludmilka [50]

Answer:

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

Step-by-step explanation:

1) Data given and notation  

s=0.68 represent the sample standard deviation  

\bar x =98.90 represent the sample mean  

n=98 the sample size  

Confidence=90% or 0.90  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .  

2) Calculating the confidence interval  

The confidence interval for the population variance is given by the following formula:  

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}  

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:  

df=n-1=98-1=97  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,97)" "=CHISQ.INV(0.95,97)". so for this case the critical values are:  

\chi^2_{\alpha/2}=120.990  

\chi^2_{1- \alpha/2}=75.282  

And replacing into the formula for the interval we got:  

\frac{(97)(0.68)^2}{120.990} \leq \sigma \leq \frac{(97)(0.68)^2}{75.282}  

0.371 \leq \sigma^2 \leq 0.596  

Now we just take square root on both sides of the interval and we got:  

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

3 0
4 years ago
What is the answer here?
Sladkaya [172]

Answer:

functions can only have one output per input there are 2 inputs of 5 and they have different outputs. You would need to get rid of (5,7) or (5,8).

8 0
3 years ago
The heights of some students are given in centimeters.
svetlana [45]
Range is biggest number minus lowest number so it’s 172-158 and that would be 14 so your answer is 14⁉️⁉️⁉️
8 0
3 years ago
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