With each line, a slope-intercept relationship (4,-1) and (-2,-1).
Y = 0 ,X = 5.
<h3>What is slope-intercept form?</h3>
The slope-intercept form is just a means of stating a line's equation so that both the slope (steepness) as well as y-intercept (where another line crosses this same vertical y-axis) are obvious. This expression is frequently referred to as y = mx + b.
<h3>According to the given information:</h3>
To begin, are using the slope formula to figure out the average slope between two points here.
Let:
x1 = 4
y1 = -1
x2 = -2
y2 = -1
m = (y2-y1)/(x2-x1)
= (-1 - (-1))/ (4-(-1))
= 0/5
= 0
So the slope is 0.
We must now calculate the y-intercept. This will be accomplished by converting a single of the points and also the slope together into a point-slope linear equation. y2-y1 = m(x2-x1).
Let’s plug in the point (5,0).
So we get y-(-0) = (0/5)(x-(-5)) ⇒ y+0
= (0/5)x + 0 ⇒ y
So,
Y = 0
X = 5
with each line, a slope-intercept relationship (4,-1) and (-2,-1).
Y = 0 ,X = 5
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There are two equations and two variables. You can solve for each variable using either the elimination method or the substitution method. Here, I believe the elimination method would be best:
5a = -4b + 5
3a = -2b + 3
You can multiply the second equation by two, so the 4b and -4b in both equations will cancel each other out when you add them. So:
5a = -4b +5
6a = 4b +6
Add both equations together.
11a = 11
a = 1
Plug in the a value into any of the previous equations:
5(1) = -4b + 5
-4b = 0
b = 0
So, since we know that b = 0, 6b is also 0.
A mountaineer climbed 1000 feet at a rate of x feet/hour
1000 = x ( t 1 ) eq1
5000 = X ( t 2) eq2 ( he climbed additional at different rate )
the rate was 10 feet / hour less than twice the first rate
X = 2x - 10 eq3
take eq1 and eq 2
( total time = t 1 + t 2 = T)
T = 1000/x + 5000/X
but X = 2x-10
T = 1000/x + 5000/( 2x -10)
T = 1000/x + 5000/( 2(x-5))
T = 1000/x + 2500 / (x-5)
Answer:
h(h(10))---> h(-4)---->10 ......hOh(10)=10
Step-by-step explanation:
Answer:
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