Step-by-step explanation:
Answer:
a) 0.80
b) 0.72
c) 0.02
Step-by-step explanation:
It is assumed that
X = Bit transmitted
Y = Bit received
= Transmissted bit is 0
= Transmissted bit is 1
= Received bit is 0
= Received bit is 1
As per the given condition
P [ | ] = 90%
P [ | ] = 100% - 90% = 10%
P [ | ] = 74%
P [ | ] = 100% - 74% = 26%
P [ Tramitted bits are 0 ] = 80%
Now calculate each situation
a)
As all the transmitted bits are o has possibilit of 80% then
P [ X = 0 ] = P [ ] = 80% = 0.80
b)
P [ X = 0, Y = 0 ] = P [ , ] = P [ | ] x P [ ] = 90% x 80% = 72% = 0.72
c)
P [ X = 1, Y = 0 ] = P [ , ] = P [ | ] x P [ ] = 10% x ( 100% - 80% ) = 10% x 20% = 2% = 0.02
Answer:
K (- 10, - 2 )
Step-by-step explanation:
To obtain the original coordinates multiply by the reciprocal of
That is multiply the image coordinates by 4
K' (- 2.5, - 0.5 ) → K (-2.5(4), (- 0.5(4) ) → K (- 10, - 2 )
"Best way to solve this equation" is very, very broad.
You could solve this equation two ways:
You could solve for x, or you could solve for k.
K has already been solved for, as it is equal to x^2.
We can also solve for x.
x = √k
Answer:
g (f(2)) = 3
Step-by-step explanation:
f (x) = x2 – 4
g(x) = x + 3
g (f (2)) =?
Find f(2) first
f (x) = x2 – 4
f (2) = 2^2- 4
= 0
Now put this in your g(x)
g(x) = x + 3
g (f(2)) = (f(2)) + 3
And u alredy know f(2) =0, so just put it in
g (f(2)) = 0 + 3
=3