1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GaryK [48]
3 years ago
12

????????????????????????????????

Mathematics
2 answers:
Tpy6a [65]3 years ago
5 0

If 2007 is "year zero", then 2010 is "year three", so that the value in 2010 can be estimated as

$2,600 (1 - 0.07)³ = $2,091.33 ≈ $2,091

ira [324]3 years ago
3 0

Answer: D

Step-by-step explanation if right please give brainleaist

You might be interested in
20 points!!!! Juan paid $5 of the price of a tennis racket, and his mom paid the rest. The tennis
snow_lady [41]
Juan payed 10% of the price
5 0
3 years ago
Simplify: 4x + 6(3x - 2)
gavmur [86]

Answer:

2 • (2x - 3) • (3x - 2)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A number, y, is equal to the difference of a larger number and 3. The same number is one-third of the sum of the larger number a
mariarad [96]

Answer:

The two equations are

y = x - 3 and

3y = x + 9

Step-by-step explanation:

The options are not well stated. I'll answer the question without the options but however, my answer will be a reflection of one of the given options.

Given:

2 statements

Required

Write equivalent of both statements as equations

Let the large number be represented by x.

From the first statement (y, is equal to the difference of a larger number and 3)

Difference means minus (-); so, this statement is represented as follows to give us the first equation:

y = x - 3

From the second statement (The same number is one-third of the sum of the larger number and 9).

This is also represented as follows to give us the second equation

y = ⅓(x + 9)

Multiply both sides by 3

3 * y = 3 * ⅓(x + 9)

3y = x + 9

So, the two equations are

y = x - 3 and

3y = x + 9

4 0
3 years ago
Read 2 more answers
I really need help with 15 and 16 please
Mandarinka [93]

Answer:

  15. 50 kg

  16a. 5 kg

  16b. 3.75 kg

Step-by-step explanation:

The formula relating force, mass, and acceleration can be solved for mass. This formula will apply to both problems. We'll use m for both "mass" and "meters". We presume you can avoid getting mixed up by understanding that meters is used in the context of acceleration: m/s².

  F = ma

  m = F/a . . . . . divide by a

__

15. m = (250 N)/(5 m/s²) = 50 kg

__

16a. m = (15 N)/(3 m/s²) = 5 kg

16b. m = (15 N)/(4 m/s²) = 3.75 kg

_____

<em>Comment on units</em>

Especially for physics problems, I like to keep the units with the numbers. It is helpful to remember that Newtons are equivalent to kg·m/s². So, dividing Newtons by acceleration in m/s² will give mass in kg. Since you're familiar with F=ma, it's not too hard to remember that the units of force (N) are the product of the units of mass (kg) and acceleration (m/s²).

6 0
3 years ago
Are these shapes similar or congruent?
aliya0001 [1]

Answer:

Congruent

Step-by-step explanation:

Hope this helps you!!

4 0
3 years ago
Other questions:
  • What's the difference between a factor and a multiple?
    14·2 answers
  • Question 1(Multiple Choice Worth 2 points)
    15·2 answers
  • PLEASE HELP WILL MARK U BRAINLIEST
    5·2 answers
  • Pauley graphs the change in temperature of a glass of hot tea over time. He sees that the function appears to decrease quickly a
    15·1 answer
  • The mean waiting time at the drive-through of a fast food from the time the order is placed to the time the order is recieved is
    15·1 answer
  • On Monday a classroom had 25 students. On Tuesday there was 33
    6·1 answer
  • (Giving brainliest! Pls have at least one sentence to explain why you chose the answer :) )
    6·2 answers
  • What is the acceleration of a 1,500-kilogram truck with a net force of 7,500 newtons?
    12·1 answer
  • Evaluate.
    10·2 answers
  • 2/5+1/3=<br> What is the answer
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!