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sergiy2304 [10]
3 years ago
9

If mBC = (9x-53) and mCD = (2x + 45) find mBAD

Mathematics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

m\angle BAD=73^o

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Find the value of x

Let

O ----> the center of the circle

we know that

Triangle BOC≅Triangle COD

m\angle BOC=arc\ BC ----> by central angle

m\angle COD=arc\ CD ----> by central angle

m\angle BOC=m\angle COD

therefore

arc\ BC=arc\ CD

substitute the given values

(9x-53)^o=(2x+45)^o

solve for x

9x-2x=45+53\\7x=98\\x=14

step 2

Find the measure of angle BAD

we know that

The inscribed angle is half that of the arc it comprises.

so

m\angle BAD=\frac{1}{2} [arc\ BC+arc\ CD]

arc\ BC=9(14)-53=73^o

arc\ CD=2(14)+45=73^o

substitute

m\angle BAD=\frac{1}{2} [73^o+73^o]=73^o

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Pythagorean triplets of 26​
Black_prince [1.1K]

Answer:

10,24,26

Answer step by step:

  • Phytagorean Theorem

The Pythagorean Theorem is a useful tool that shows how the sum of the areas of three intersecting squares can determine the side lengths of a right triangle.

  • Phytagorean Formula

\large{ \boxed{c =  \sqrt{ {a}^{2} +  {b}^{2}  }} }

With:

c = hypotenusa

a = upright side

b = pedestal side

Keep in mind that the Pythagorean formula only applies to right-angled triangles

  • Continue to discussion

26 =  \sqrt{ {10}^{2} +  {24}^{2}  }

26 =  \sqrt{(10 \times 10) + (24 \times 24)}

26 =  \sqrt{100 + 576}

26 =  \sqrt{676}

26 =  \sqrt{26 \times 26}

26 =  \sqrt{ {26}^{2} }

26 = 26

conclusion that prove that 10,24,26 is a Pythagorean triple.

  • Learn More About Phytagorean Theorm

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2 years ago
The picture above is my question. thank you. ​
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Answer:

<

Step-by-step explanation:

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Solve the following equation to find the value of x:<br> 4x + 10 = 22
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4x=22-10
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4. Two cylinders have dimensions in the ratio of 2:3. The smaller cylinder has a surface area of 16 cm.
Zarrin [17]

Answer:

(cross multiply)

2:3

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