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3 years ago

16.45 markdown 33% what’s the anwser

Mathematics

2 answers:

Art [367]3 years ago

6 0

<h2>Greetings!</h2>

Answer:

= 11.02

Step-by-step explanation:

Firstly, we need to find the percentage of the amount left first. This can be done by subtracting the percentage from 100:

100 - 33 = 67

To find the percentage of something, you need to use the following equation:

Amount x $\frac{percentage}{100}$

Simply plug the given values in:

16.45 x $\frac{67}{100}$ = 11.02

So the answer is 11.02!

<h2>Hope this helps!</h2>

Fittoniya [83]3 years ago

5 0

dude, use a calculator

Step-by-step explanation:

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The answer is 17 and 31

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3 years ago

I need another help again my bros

andrew11 [14]

Answer:

a = 15.59 c= 31.18

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3 years ago

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1) find the equation of the line parallel to

In-s [12.5K]

<u>Answer:</u>

1) The equation of the line parallel to x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is 2y = 5x -12

<u>Solution:</u>

<u><em>1) find the equation of the line parallel to x-5y=6 and through (4,-2).</em></u>

Given, line equation is x – 5y = 6

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}$

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }$

$y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14$

Hence, the line equation is 5y = x -14

<u><em> 2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)</em></u>

$\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15$

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}$

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line $\times$ slope of given line = -1

slope of required line = $-1 \times \frac{5}{-2}=\frac{5}{2}$

And it passes through (2, -1)

Now, using point slope form

$\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}$

Hence, the line equation is 2y = 5x -12

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3 years ago

I need help Raj plotted point L in the coordinate plane below.

Ivenika [448]

Answer:

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Step-by-step explanation:

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3 years ago

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Given that 3(x-c)=2x+5 where c is an integer, shoe that x cannot be a multiple of 6

olga nikolaevna [1]

Answer:

The explanation in the procedure

Step-by-step explanation:

we have

$3(x-c)=2x+5$

solve for c

$3x-3c=2x+5$

$3c=3x-2x-5$

$3c=x-5$

$c=(x-5)/3$

For $x=6$ -----> Find the value of c

$c=(6-5)/3=1/3$ ------> is not an integer

therefore

x cannot be a multiple of 6

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3 years ago