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Readme [11.4K]
3 years ago
13

Sushant is a new manager and he wants to share his ideas and working protocol with his team.Compare the advantages and disadvant

ages of oral and written communication and suggest him which form of communication would be more effective.
Computers and Technology
1 answer:
saw5 [17]3 years ago
3 0

Answer:

Advantages of Oral Communication

  1. Use of visual aids like PowerPoint presentation while explaining his ideas and working protocols would help his team to understand him better.
  2. There is a spontaneous response from the staff which is more genuine than written response.

Disadvantages of Oral Communication

  1. It could prove to be a problem if Sushant has stage fright or is not an effective communicator, which could form an impression of him by the staff.
  2. Staff may forget some of Sushant's words as no memory is as reliable as written information.

Advantages of Written Communication

  1. A well written memo explains the ideas and working protocols that Sushant wants to relay to the staff.
  2. There could be a questionnaire for the staff to give feedback.
  3. Aims, objectives are clearly stated.

Disadvantages of Written Communication

  1. If the written material is too lengthy, it could be a problem to learn or memorise.

It is recommended that Sushant should use written form of communication to convey his ideas and working protocols as it is more effective.

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Which of the following bit patterns represents the value -9 in two’s complement notation?
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B. 11110111

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Binary representation of -9 would involve calculating the twos complement representation of 00001001

First we compute the ones complement of this number by reversing the bits.

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Next we calculate the twos complement representation by adding 1 to the ones complement.

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5 0
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A large population of ALOHA users manages to generate 50 requests/sec, including both originals and retransmissions. Time is slo
krok68 [10]

Answer:

The answer is below

Explanation:

Given that:

Frame transmission time (X) = 40 ms

Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request

a) Probability that there is success on the first attempt = e^{-G}G^k but k = 0, therefore Probability that there is success on the first attempt = e^{-G}=e^{-2}=0.135

b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)

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6 0
3 years ago
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