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MrMuchimi
3 years ago
15

Which of the following is the minimum value of the equation y=2x^2+5

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0
Plug in 0 for x and you get 5. Which is your answer :)
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If you are able to save, $150 dollars per month-how many months will it take you to
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16.66months

Step-by-step explanation:

2500/150

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CAN ANYONE HELP ANSWER THIS
bija089 [108]

9514 1404 393

Answer:

  58

Step-by-step explanation:

The marked points on the graph show that the number of hot cocoas sold decreases by 6 when the temperature goes up by 6 degrees. That is, the line has a slope of -1. The y-intercept is 100, so the equation of the line can be written as ...

  y = mx +b . . . . . line with slope m and y-intercept b

  y = -x +100

Then for x = 42, the expected value of y is ...

  y = -42 +100 = 58

Mei Mei can expect to sell 58 hot cocoas on a day when the high is 42°F.

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2 years ago
Which of the following expressions represents the distance between 5/2 and 4 7/8 on a number line?
hjlf

Answer:

<h2>C. None of the above</h2>

Step-by-step explanation:

\text{The formula of a distance between x and y on a number line:}\\\\d=|b-a|=|a-b|\\\\\text{We have}\ a=\dfrac{5}{2}\ \text{and}\ b=4\dfrac{7}{8}.\ \text{The distance:}\\\\d=\left|\dfrac{5}{2}-4\dfrac{7}{8}\right|=\left|4\dfrac{7}{8}-\dfrac{5}{2}\right|}

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2 years ago
Factorise this expression as fully as possible 2x^2+6x
AURORKA [14]

Answer:

(Factor out 2x from the expression)

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3 0
3 years ago
The end behaviour for the polynomial function h(x)=−x3+x4−2x+1 h ( x ) = - x 3 + x 4 - 2 x + 1 is: x→−[infinity], y→−[infinity]
Goryan [66]

Answer:

\text{As  } x \to \infty, y  \to \infty,$and as  x \to -\infty, y  \to \infty

Step-by-step explanation:

Given the polynomial function: h(x)=-x^3+x^4-2x+1

To examine its end behavior, we create a table of values that we can then examine.

\left|\begin{array}{c|c}x&h(x)\\--&--\\-4&329\\-3&115\\-2&29\\-1&5\\0&1\\1&-1\\2&5\\3&49\\4&185\end{array}\right|

From the table, we see a repeating pattern of positive values of h(x) with h(1)=-1 being an axis of symmetry.

Therefore, as:

x \to \infty, h(x)  \to \infty\\x \to -\infty, h(x)  \to \infty

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