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3 years ago

Which of the following is the minimum value of the equation y=2x^2+5

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

7 0

Plug in 0 for x and you get 5. Which is your answer :)

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2+2 wrong answers only ❤✨ also have an awesome day

juin [17]

Answer:

it's equal to 22 :)

thx you too and thx for the points

3 0

3 years ago

Read 2 more answers

Please help and show the work

ozzi

9514 1404 393

Answer:

Step-by-step explanation:

If you multiply the first equation by 2, you get ...

2x +2y = 4

When you compare this to the second equation ...

2x +2y = 8

you realize there are <em>no values of x and y that can satisfy both equations</em>. There are no solutions.

3 0

2 years ago

What is the factorization of 3x2 – 8x + 5?

ELEN [110]

we have

$3x^{2} -8x+5$

Equate the expression to zero to find the roots

$3x^{2} -8x+5=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$3x^{2} -8x=-5$

Factor the leading coefficient

$3(x^{2} -(8x/3))=-5$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$3(x^{2} -(8x/3)+(16/9))=-5+(16/3)$

$3(x^{2} -(8x/3)+(16/9))=(1/3)$

Rewrite as perfect squares

$3(x-(4x/3))^{2}=(1/3)$

$(x-(4x/3))^{2}=(1/9)$

square roots both sides

$(x-\frac{4}{3})=(+/-) \sqrt{\frac{1}{9}}$

$x=\frac{4}{3}(+/-) \frac{1}{3}$

the roots are

$x=\frac{4}{3}+ \frac{1}{3}=\frac{5}{3}$

$x=\frac{4}{3}- \frac{1}{3}=\frac{3}{3}=1$

$3x^{2} -8x+5=3(x-\frac{5}{3})(x-1)=(3x-5)(x-1)$

therefore

<u>the answer is the option</u>

$(3x-5)(x-1)$

6 0

2 years ago

Read 2 more answers

Which transformation(s) of circle C prove that circle A is similar to circle C ?

Bas_tet [7]

It similar Because there both in the 2s

6 0

3 years ago

How do you solve this equation? 8=3(q-10)-10

IRISSAK [1]

Q = 16
View the attached image for work!

6 0

3 years ago