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Helen [10]
3 years ago
9

Consider an element Z that has two naturally occuring isotopes with the following percent abundances: the isotope with a mass nu

mber 22.0 is 65.0% abundant; the isotope with a mass number 24.0 is 35.0% abundant. What is the average atomic mass for element Z? Round your answer to the hundredth.
Chemistry
1 answer:
rodikova [14]3 years ago
3 0

Answer:

Z=22.70

Explanation:

It is given that,

An element Z that has two naturally occurring isotopes with the following percent abundances as follows :

The isotope with a mass number 22 is 65.0% abundant; the isotope with a mass number 24 is 35.0% abundant.

The average atomic mass for element Z is given by :

Z=\dfrac{22\times 65+24\times 35}{100}\\\\Z=22.7

So, the average atomic mass for element Z is 22.70.

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Analysis of an ore of calcium shows that it contains 13.61 g calcium and 21.77 g oxygen in a 46.28-g sample. Calculate the perce
kondor19780726 [428]

Answer:

29.41% of Calcium and 47.04% of Oxygen

Explanation:

The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.

The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:

13.61g / 46.28g * 100 = 29.41% of Calcium

And percent composition of Oxygen is:

21.77g / 46.28g * 100 = 47.04% of Oxygen

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3 years ago
You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans
OLga [1]

Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

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Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

Cf = concentration of the final solution

Vf = volume of the final solution

Then, replacing with the data:

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Notice that any concentration unit can be used, as long as the units of the concentration of the stock and final solution are the same.

4 0
3 years ago
Round to 4 significant<br> figures.<br> 153.587
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I believe 153.6 is the answer.
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