Yo has to distribute and add like terms
distributeiv propoerty
a(b+c)=ab+ac aka
a(b-c)=ab-ac
5(4n-11)-3n+20=17n-35
distribuet
5*4n=20n
5*11=55
20n-55-3n+20=17n-35
move like terms together
20n-3n+20-55=17n-35
20-3=17
20-55=35
17n-35=17n-35
true
C. 14•8 over 2.
A= bh over 2
Answer:
It's the first option.
Step-by-step explanation:
y = cos x transformed to cos (x - π/2) moves the graph π/2 units to the right.
Multiplying by 3 to give 3 cos(x - π/2) stretches the graph 3 units parallel to the y-axis and adding 3 to this moves the graph up 3 units.
So the required equation is y = 3(cos x - π/2) + 3.
Answer:
b^2√30b
Step-by-step explanation:
√30b^5 - Original
Break down the radical with its factors (factor tree)
√3*2*5*b*b*b*b*b
See what perfect squares you can take out (Can take out four b terms) You cant take out any perfect squares involving 30 since there are no perfect squares
b^2√3*2*5*b
b^2√30b
Answer:
81
Step-by-step explanation:
let the terms be a,ar,ar²
r=2/3
a+a(2/3)+a(2/3)²=171
multiply by 9
9a+6a+4a=171×9
19 a=171×9
a=(171×9)/(19)
a=9×9=81
