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butalik [34]
3 years ago
10

What are the domain and range of the real-value function f(x) =-2+√x+7

Mathematics
2 answers:
prohojiy [21]3 years ago
8 0

The given function -2+√x+7 is a square root function.

The expression inside the square root of a unction cannot be negative. Because if it will be negative then the function will be imaginary. So, expression inside the square root must be positive or zero. Hence, to find the domain of a square root function set the expression inside the square root as more than or equal to zero.

So, x+7≥0

x+7 -7 ≥0-7 Subtract 7 from each sides to isolate x.

x≥ -7

So, the domain of the given function is x≥ 7.

Notice that if we will plug in any value which is more than or equal to 7then we will get y >=-2 only. It must be -2+.

So, range of this function is y>=-2.

stiks02 [169]3 years ago
4 0

Because the function f(x) =-2+√x+7 has √x, x should be more or equal 0.

Domain is x≥0, or [0,+∞).

The smallest value of x=0, so the smallest value of f(x) is f(0) =-2+√0+7=5,

so range is f(x)≥5, or [5, +∞).

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densk [106]
54% = 54/100 = 27/50

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Hope it helped :)
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3 years ago
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If x^2-x-6 and x^2+3x-18 hacpve a common factor (x-a) then find the value of a.​
DedPeter [7]

Answer:

a = 3

Step-by-step explanation:

Factor both expressions

x² - x - 6

Consider the factors of the constant term (- 6) which sum to give the coefficient of the x- term (- 1)

The factors are - 3 and + 2 , since

- 3 × 2 = - 6 and - 3 + 2 = - 1 , thus

x² - x - 6 = (x - 3)(x + 2)

-----------------------------------

x² + 3x - 18

consider factors of constant term (- 18) which sum to give the coefficient of the x- term (+ 3)

The factors are + 6 and - 3 , since

6 × - 3 = - 18 and 6 - 3 = + 3 , thus

x² + 3x - 18 = (x + 6)(x - 3)

Both expressions have a common factor of (x - 3)

Compare with (x - a ), then a = 3

3 0
3 years ago
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Please Help me<br> This is due ASAP!
77julia77 [94]

Answer:

20 nickels

23 dimes

Step-by-step explanation:

hope this helps!

7 0
3 years ago
Travis just got a new credit card that offers inductors APRof 3.6% for first 3 months and standard APR of 14.4% thereafter. If i
Makovka662 [10]

Answer:

Month 1 : 0.002988

Month 2: 0.00299692814

Month 3: 0.00300588297

Step-by-step explanation:

Since we're only finding the interest for the first three months, it's easy to do it by performing the simple interest formula. But first, we need divide 3 by 12, since we calculate interest using years. 3/12 = 1/4 = 0.25

The standard simple interest calculation is done by multiplying the starting amount, by the interest, by the time, then dividing by 100 to put it into a percentage.

1 month = 1/12 or approximately 0.083 of the year.

Let's say P = 1. For the first month, it will be 1 x 3.6 x 0.083 = 0.2988 / 100

The second month, (1 + 0.002988) * 3.6 * 0.083 = 0.299692814 / 100

The third month, (1.002988 + 0.00299692814) x 3.6 x 0.083 = 0.300588297/100

Given the initial amount be 1, those would be the periodic interest rate during the first three months.

5 0
3 years ago
How would i anser this select all the ratios equivalent to 4:6
Natali5045456 [20]
If we try to simplify the ratio or try to multiply both by any number, we will get the equivalent ratio


Like :

\frac{4}{6}  \\


Divide ( simplify ) by 2


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Or multiply by any number,



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From the example, 2 / 3 and 8 / 12 are equivalent ratios to 4 / 6
6 0
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