The necessary solution that would be used to fill in the blanks would be
- perpendicular
- is the center of
- Circumscribed
<h3>How to find the center of the circle</h3>
The way that Quintin would be able to do this would be the center of the circumferential triangle is equidistant from the vertices.
The center is going to be the intersection of the bisectors of the three sides of the given triangle.
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perpendicular bisectors, is the center of, circumscribed
Answer:
Answer is B
Step-by-step explanation:
Answer:
F=3
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3(6−f)−4=3f−4
(3)(6)+(3)(−f)+−4=3f+−4(Distribute)
18+−3f+−4=3f+−4
(−3f)+(18+−4)=3f−4(Combine Like Terms)
−3f+14=3f−4
−3f+14=3f−4
Step 2: Subtract 3f from both sides.
−3f+14−3f=3f−4−3f
−6f+14=−4
Step 3: Subtract 14 from both sides.
−6f+14−14=−4−14
−6f=−18
Step 4: Divide both sides by -6.
−6f−6=−18−6f=3
Answer:
f=3
