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tekilochka [14]
4 years ago
15

Complete factorization

Mathematics
1 answer:
Arte-miy333 [17]4 years ago
6 0
(3x-10) (3x-10)

Both of the 10's have to be negative because -10 x -10 = 100
and if you use foil -30 + -30 = -60
You might be interested in
Assume that t varies jointly as r and q2². If t=320 when r=5 and q = 4, what is the value of q when r= 1 and t= 196?
Harrizon [31]

Step-by-step explanation:

t = k(r)( {q}^{2} )

320 = k(5)( {4}^{2} )

320 = 80k

k = 4

196 = 4(1)( {q}^{2} )

49 =  {q}^{2}

q = 7

4 0
3 years ago
The table shows a linear function.
Elza [17]

Answer:

a) I used the equation x=-5; f(x)=-11 and x=-4; f(x)=-3. We get the range = -3-(-11)=8

b) I used the equation x=-5; f(x)=-11 and x=-3; f(x)=5. We get the range = 5-(-11)=16

c) I used the equation x=-5; f(x)=-11 and x=-2; f(x)=13. We get the range = 13-(-11)=24

d) Range of input is equal with the ratios of the output. You can find the pattern of output above 8,16,and 24 can divided by 8 and give the result 1,2 and 3

4 0
3 years ago
Find the value of x that satisfy the equation -4(x - 4) = 20
Firdavs [7]

Answer:

x = -1

Step-by-step explanation:

If you need step by step just let me know!

Hopefully that helps!

7 0
3 years ago
Read 2 more answers
How do I solve this problem?
german
Take the angle then multiple them by what ever needs to be, then finish it. and sorry not in geometry abd i am not good with angles.
8 0
4 years ago
You are interested in purchasing a new car. One of the many points you wish to consider is the resale value of the car after 5 y
gulaghasi [49]

Answer:

The 95​% confidence interval for the true mean resale value of a​ 5-year-old car of this​ model

(11,688.68 , 12,511.32)

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given sample size 'n' = 17

mean of the sample x⁻ = 12,100

Standard deviation of the sample (S) = 800

The 95​% confidence interval for the true mean resale value of a​ 5-year-old car of this​ model

(x^{-} - t_{0.05} \frac{S}{\sqrt{n} } , x^{-} + t_{0.05} \frac{S}{\sqrt{n} } )

<u><em>Step(ii):-</em></u>

<u><em>Degrees of freedom ν =n-1 = 17-1 =16</em></u>

<u><em></em></u>t_{(16 , 0.05)} = 2.1199<u><em></em></u>

The 95​% confidence interval for the true mean resale value of a​ 5-year-old car of this​ model

(x^{-} - t_{0.05} \frac{S}{\sqrt{n} } , x^{-} + t_{0.05} \frac{S}{\sqrt{n} } )

(12,100 - 2.1199\frac{800}{\sqrt{17} } , 12,100 + 2.1199 \frac{800}{\sqrt{17} } )

(12,100 - 411.32 , 12,100 + 411.32)

(11,688.68 , 12,511.32)

3 0
3 years ago
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