15-m=22-8m solve for m

What is the true solution to 3 in 2 + in 8 = 2 in (4x)

The first step for solving this equation is to determine the defined range.
3㏑(2) + ㏑(8) = 2㏑(4x), x > 0
Write the number 8 in exponential form.
3㏑(2) + ㏑(2³) = 2㏑(4x)
Using ㏑( $a^{x}$ ) = x × ㏑(a),, transform the expression.
3㏑(2) + 3㏑(2) = 2㏑(4x)
Now collect the like terms on the left side of the equation.
6㏑(2) = 2㏑(4x)
Switch the sides of the equation.
2㏑(4x) = 6㏑(2)
Using x × ㏑(a) = ㏑( $a^{x}$ ),, transform the expression on the left side of the equation.
㏑((4x)²) = 6㏑(2)
Using x × ㏑(a) = ㏑( $a^{x}$ ),, transform the expression on the right side of the equation.
㏑((4x)²) = ㏑( $2^{6}$ )
Since the bases of the logarithms are the same,, you need to set the arguments equal.
(4x)² = $2^{6}$
Take the square root of both sides of the equation and remember to use both the positive and negative roots.
4x = +/- 8
Now separate the equation into 2 possible cases.
4x = 8
4x = -8
Solve the top equation for x.
x = 2
Solve the bottom equation for x.
x = 2
, x > 0
x = -2
Lastly,, check if the solution is in the defined range to find your final answer.
x = 2
This means that the correct answer to your question is x = 2.
Let me know if you have any further questions
:)

5 0

3 years ago

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What is the first step in evaluating the expression shown below?

zysi [14]

Answer:

the answer is A

Step-by-step explanation: because the way you work out problems with parenthesis is Parenthesis Exponents Multiplication Division Adding Subtraction and what ever id in the parenthesis comes first

5 0

3 years ago

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The length of a rectangle is 1 less than twice the width.

vladimir1956 [14]

$w-width\\2w-1-length\\w(2w-1)=2w^2-w-the\ area\\28\ ft^2-the\ area\\\\\text{The equation:}\\\\2w^2-w=28\qquad\text{subtract 28 from both sides}\\\\2w^2-w-28=0\\\\2w^2-8w+7w-28=0\\\\2w(w-4)+7(w-4)=0\\\\(w-4)(2w+7)=0\iff w-4=0\ \vee\ 2w+7=0\\\\w-4=0\qquad\text{add 4 to both sides}\\\boxed{w=4}\\\\2w+7=0\qquad\text{subtract 7 from both sides}\\2w=-7\qquad\text{divide both sides by 2}\\w=-3.5$

7 0

3 years ago

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(2x^2+x+3)/(x-2)with remainder

Leni [432]

Answer:

2x+5 r. 13

Step-by-step explanation:

So using long division, you can solve for the quotient and the remainder.

Please look at the attached for the solution.

Step 1: need to make sure that you right the terms in descending order. (If there are missing terms in between, you need to fill them out with a zero so you won't have a problem with spacing)

Step 2: Divide the highest term in the dividend, by the highest term in the divisor.

Step 3: Multiply your result with the divisor and and write it below the dividend, aligning it with its matched term.

Step 4: Subtract and bring down the next term.

Repeat the steps until you cannot divide any further. If you have left-overs that is your remained.