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MAXImum [283]
3 years ago
8

Simplify the following expression.​

Mathematics
1 answer:
aliina [53]3 years ago
6 0
The answer to the question

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4. Lisa walked 48 blocks in 3 hours.<br> blocks per hour
dlinn [17]

Answer:

The number of blocks in one hour is the same that the unit rate, so 16 blocks per hour

Step-by-step explanation:

we know that

To find out the unit rate, divide the total blocks by the total time

so

\frac{48}{3}\ \frac{blocks}{hours}=16\ \frac{blocks}{hour}

3 0
3 years ago
Write the two conditional statements that form the given biconditional.Then decide whether the biconditional is a good definitio
stiks02 [169]
If three points are collinear, then they are coplanar. TRUE

If three points are coplanar, then they are collinear. FALSE
6 0
3 years ago
1
Alexxandr [17]

Answer: 1/5

Step-by-step explanation:

it would be 1/5 because you trying to get 2 numbers out of ten cards so it would be 2/10 simplified to 1/5

3 0
3 years ago
What are the x-intercepts of the graph of the function f(x) = x2 + 4x – 12? (–6, 0), (2,0) (–2, –16), (0, –12) (–6, 0), (–2, –16
Margaret [11]

Answer:

(-6, 0) and (2, 0)

Step-by-step explanation:

To find the x-intercepts, we can factor the expression:

f(x) = x² + 4x - 12

2 factors of -12 that add up to 4 are 6 and -2

(x + 6)(x - 2)

Set each factor equal to 0 and solve for x:

x + 6 = 0

x = -6

x - 2 = 0

x = 2

So, the x intercepts are (-6, 0) and (2, 0)

4 0
3 years ago
A(7-1), B(6, 4) and C(5, 5) are three
Andrej [43]

Answer:

The answer is below

Step-by-step explanation:

The equation of the line passing through two points is given by:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\

The equation of line AB is:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-(-1)=\frac{4-(-1)}{6-7}(x-7)\\\\y+1=-5(x-7)\\y+1=-5x+35\\y=-5x+34

The midpoint of two lines is given as:

x=\frac{x_1+x_2}{2}, y=\frac{y_1+y_2}{2}\\midpoint\ of\ AB \ is:\\x=\frac{7+6}{2}=6.5, y=\frac{-1+4}{2}=1.5\\ = (6.5,1.5)

The equation of line AC is:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-(-1)=\frac{5-(-1)}{5-7}(x-7)\\\\y+1=-3(x-7)\\y+1=-3x+21\\y=-3x+20

The midpoint of two lines is given as:

x=\frac{x_1+x_2}{2}, y=\frac{y_1+y_2}{2}\\midpoint\ of\ AB \ is:\\x=\frac{7+5}{2}=6, y=\frac{-1+5}{2}=2\\ = (6,2)

The product of the slope of a perpendicular bisector of a line and the slope of the line is -1. That is m1m2 = -1

The slope of the perpendicular bisector of AB is:

m(-5)=-1

m=1/5

The equation of the perpendicular bisector of AB passing through (6.5,1.5) is:

y-y_1=m(x-x_1)\\y-1.5=\frac{1}{5}(x-6.5)\\y=\frac{1}{5} x-8.25

The slope of the perpendicular bisector of AB is:

m(-3)=-1

m=1/3

The equation of the perpendicular bisector of AB passing through (6,2) is:

y-y_1=m(x-x_1)\\y-2=\frac{1}{3}(x-7)\\y=\frac{1}{3} x-4.33

2) The point of intersection is gotten by solving y = 1/5 x -8.25 and y = 1/3 x-4.33 simultaneously.

Subtracting the two equations from each other gives:

0= -0.133x - 3.92

-0.133x = 3.92

x = -29.5

Put x = -29.5 in y = 1/5 x -8.25 i.e:

y = 1/5 (29.5) -8.25

y = -14.16

The point of intersection is (-29.5, -14.16)

4 0
3 years ago
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