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2 years ago

Solve y=-x+2 and y=-2x-1 as a graph, substitution, or elimination?

Mathematics

1 answer:

kotegsom [21]2 years ago

8 0

Answer:

(- 3, 5 )

Step-by-step explanation:

Given the 2 equations

y = - x + 2 → (1)

y = - 2x - 1 → (2)

Using substitution method.

Substitute y = - x + 2 into (2)

- x + 2 = - 2x - 1 ( add 2x to both sides )

x + 2 = - 1 ( subtract 2 from both sides )

x = - 3

Substitute x = - 3 into (1)

y = - (- 3) + 2 = 3 + 2 = 5

Solution is (- 3, 5 )

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Answer:

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yaroslaw [1]

Answer:

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Step-by-step explanation:

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2 years ago

I need help bruv. For the function y=x^2 - 5x - 6 .

lara [203]

Answer:

a. Vertex = (2.5,-12.25)

b. y-intercept = (0,-6)

c. x-intercept = (6,0) ; (-1,0)

Step-by-step explanation:

Your equation is written as:

$y = ax^{2} + bx +c$

The easiest way to find the vertex is writing the equation this way:

$y = a(x-h)^{2}+k$

Being the vertex (h,k)

So first complete the square

$y = x^{2} -5x -6 \\y = x^{2} - 2(2.5x) -6 \\y = x^{2} - 2(2.5x) +2.5^{2} - 2.5^{2} -6 \\y = (x^{2} -2(2.5x) + 2.5^{2}) -6.25 - 6 \\y = (x-2.5)^{2} -12.25$

Vertex : (2.5,-12.25)

To find the y-intercept you need to replace the equation when x = 0 and get y

$y = (0)^{2} - 5(0) -6\\y = - 6$

To find the x-intercept you need to replace the equation when y = 0 and get x

$0 = x^{2} - 5x -6 \\0 = (x-6)(x+1)\\x = 6\\x = -1$

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