The statement that correctly summarizes the trend in electron affinity is the second option: it tends to be more negative across a period".<span> Electron affinity is the energy absorbed or released by a neutral atom when it absorbs an electron. The more negative the electron affinity the higher the affinity of the atom for an additional electron. So as the electronegativity trends to increase across a period, indicating that the atoms of the left side pull stronger the electrons, the fact that the electron affinity is more negative across a period tells that the atoms to the left accept better an additional electron.</span>
Answer:
1.38*10^4 L or 0.138*10^2 m^3
Explanation:
The balanced equation for the reaction is:
⇒
In the chemical equation above, 3 moles of hydrogen gas react with 1 mole of nitrogen gas to produce 2 moles of ammonia gas. A STP, 1 mole of gas is equivalent to 22.4 L. Therefore,
6.9 m^3 of nitrogen gas will be equivalent to 6900 L. In addition, 6900L will be equivalent to 6900/22.4 = 308.036 moles
1 mole of nitrogen produced 2 moles of ammonia gas, therefore, 308.04 moles of nitrogen gas would produce 2*308.036 moles = 616.07 moles of ammonia gas
At STP, 1 mole of gas is equivalent to 22.4 L, thus 616.07 moles will be equivalent to 22.4*616.07 = 13800 L or 13.8 m^3
This is the correct equilibrium represented in the question
Blue + 4 Br- (aq) <---> green + 6H2O (l)
Answer:
Addition of NaBr supplied the Br- ions which moved the equilibrium position towards the right hand side. The forward reaction is endothermic hence its rate decreases when the reaction mixture is placed in an ice bath.
Explanation:
Blue + 4 Br- (aq) <---> green + 6H2O (l)
Looking at the equilibrium represented above, addition of Br- moves the equilibrium towards the right hand side, that is, the green colour. Addition of NaBr increases the Br- concentration and drives the forward reaction hence the equilibrium position shifts towards the right hand side. The fact that the solution turns blue when placed in ice bath reveals that the forward reaction is endothermic. Decreasing the temperature shifts the equilibrium position towards the left hence the resurgence of the blue colour.
Your answer is 2 goes to the right and twice to the left
Answer:
D. The side chains of D-Arg and D-Lys are not positioned to bind correctly at the active site
Explanation:
Stereospecificity is the ability to distinguish between stereoisomers of of a particular compound. L- and D- structures of compounds in living organisms are usually present in only one form due to stereospecificity. For example, naturally occuring amino acids in proteins are usually present as L-isomers.
Since enzyme are proteins, their active sites are composed of L-amino acid and they show stereospecificity in the reactions they catalyze. In their binding sites, only substrates complementary in structure can bind in order for catalysis to proceed. Therefore, only amino acids in the L- configuration are complementary to the active site of enzymes.
In the case of serine proteases, The side chains of -Arg and D-Lys will not be positioned properly for binding at the binding site of serine proteases, therefore, no catalysis will occur. On the other hand, L-Arg and L-Lys can bind to the catalytic site of serine proteases since they are complementary fits to the active site of the enzymes.