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3 years ago

"Polly Pocket picked a purple plant" is an example of:

Chemistry

1 answer:

ale4655 [162]3 years ago

6 0

Answer:

Alliteration

Explanation:

In "Polly Pocket picked a purple plant" the first letter of each of the words repeats. "Polly Pocket picked a purple plant"

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Lol your answer is c

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3 years ago

Annie is trying to attract her metal pencil box with a magnet from the other side of her desk. The pencil box does not move. Wha

elena55 [62]

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4 years ago

What is the main factor that prevents the growth of tropical plants in the northern part of the us

Inessa05 [86]

Extreme weather e.g. snow and cold weather. Another main contributing factor is that many places have a long dry season.

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3 years ago

What is a molecular formula?

polet [3.4K]

The symbolic representation of its compound and its composition.

or a chemical formula that indicates the kinds of atoms and the number of each kind in a molecule of a compound.
ANSWER IS B

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3 years ago

A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the

baherus [9]

Answer: 1. $9.08\times 10^{-6}$ moles

2. 90 mg

Explanation:

$O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus $4.54 \times 10^{-6}$ moles of ozone is removed by = $\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6}$ moles of sodium iodide.

Thus $9.08\times 10^{-6}$ moles of sodium iodide are needed to remove $4.54\times 10^{-6}$ moles of $O_3$

2. $\text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = $\frac{2}{1}\times 0.0003=0.0006$ moles of sodium iodide.

Mass of sodium iodide= $moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg$ (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of $O_3$ .

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3 years ago