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Delicious77 [7]
1 year ago
9

If 2.8X10⁻¹⁰% of the atoms of a radioactive isotope disintegrate in 1.0 yr, what is the decay constant of the process?

Chemistry
1 answer:
Marizza181 [45]1 year ago
7 0

Decay constant, proportionality between the size of a population of radioactive atoms and the rate at which the population decreases because of radioactive decay.

<h3>What is decay constant value?</h3>

The rate of disintegration is proportional to the number of atoms at any point in time and the constant of proportionality is called the radioactivity decay constant. The radioactive decay constant for Radium B is approximately 4.3 × 10−4 s−1.

<h3>What is decay constant unit?</h3>

Definition. The decay constant (symbol: λ and units: s−1 or a−1) of a radioactive nuclide is its probability of decay per unit time. The number of parent nuclides P therefore decreases with time t as dP/P dt = −λ. The energies involved in the binding of protons and neutrons by the nuclear forces are ca.

Learn more about decay constant here:

<h3>brainly.com/question/16623902</h3><h3 /><h3>#SPJ4</h3>

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What’s a chemical property
abruzzese [7]

Answer:

A chemical property is any of a material's properties that becomes evident during, or after, a chemical reaction; that is, any quality that can be established only by changing a substance's chemical identity. ... They can also be useful to identify an unknown substance or to separate or purify it from other substances.

6 0
3 years ago
What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?
sertanlavr [38]
Answer is: volume of H₂SO₄ is 42.1 mL.<span>
Chemical reaction: H</span>₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.<span>
c(H</span>₂SO₄) = 0,4567 M = 0,4567 mol/L.<span>
V(NaOH) = 30 mL </span>÷ 1000 mL/L <span>= 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H</span>₂SO₄) : n(NaOH) = 1 : 2.<span>
n(H</span>₂SO₄) = 0,01926 mol.<span>
V(H</span>₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).<span>
V(H</span>₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.<span>
V(H</span>₂SO₄<span>) = 0,0421 L = 42,1 mL.</span>
3 0
3 years ago
A) A cat dish has a mass of 1975 g and a volume of 7500ml. What is the overall density of the cat dish? B) find the maximum mass
maxonik [38]
What's the answer? It asked to be 20 characters long so just writing this.
5 0
3 years ago
How many moles in 3.69 x 10^30 molecules of carbon dioxide?
Sedaia [141]

0.612 \times 10^{7} \text { moles of } \mathrm{CO}_{2} are present in 3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}

<u>Explanation:</u>

It is known that each mole of an element is composed of avagadro's number of molecules. So if we need to determine, we need to divide the number of molecules with the avagadro's number.

So,

    1 mol of element =6.02 \times 10^{23} molecules of element

As here 3.69 \times 10^{30} molecules of carbon di oxide is given. So the moles in it will be

   No. of moles of carbon dioxide = \frac{3.69 \times 10^{30}}{6.02 \times 10^{23}}

    No. of moles = 0.612 \times 10^{7} moles of carbon dioxide.

Thus,

0.612 \times 10^{7} of carbon dioxide are present in 3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}.

4 0
3 years ago
Consider this row in the periodic table of elements. As we move from left to right, across the row, the elements ... A) change f
Yuri [45]

B) change from metals to nonmetals.

4 0
3 years ago
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