Answer:
4 moles of water
Explanation:
this is a combustion reaction, so the balanced equation is: 2C2H6 + 7O2 → 4CO2 + 6H2O.
the molar mass of C2H6 is 30.07g, so 40.0 g of C2H6 is 1.33 moles of C2H6.
mole ratio of H2O to C2H6 is 6/2, or 3.
1.33 moles C2H6 * 3 moles H2O/1 mole C2H6 = 4 moles H2O
Answer:
Explanation: Q1 = mc(ice) ΔT (ice warms)
Q2 = ms (ice melts)
Q3 = mc((water) ΔT (water warms)
Q4 = mr (water boils)
Q5 = mc(vapour)ΔT
Answer:
223 g O₂
Explanation:
To find the mass of oxygen gas needed, you need to (1) convert moles Al to moles O₂ (via the mole-to-mole ratio from reaction coefficients) and then (2) convert moles O₂ to grams O₂ (via the molar mass). When writing your ratios/conversions, the desired unit should be in the numerator in order to allow for the cancellation of the previous unit. The final answer should have 3 sig figs because the given value (9.30 moles) has 3 sig figs.
4 Al + 3 O₂ ----> 2 Al₂O₃
^ ^
Molar Mass (O₂): 32.0 g/mol
9.3 moles Al 3 moles O₂ 32.0 g
------------------- x --------------------- x -------------------- = 223 g O₂
4 moles Al 1 mole
Answer:
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