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Marta_Voda [28]
3 years ago
13

Determine which relation is a function.

Mathematics
1 answer:
Firdavs [7]3 years ago
5 0
By=x+2, as this is the only equation that shows the relation between 2 variables
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The line segment joining the points ( 3,-4) and (1,2) is trisected at the points P and Q . If the coordinates of P and Q are (p
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Answer:

P = 7/3 and q = 0

Step-by-step explanation:

The given parameters are;

The endpoints of the segment are, (3, -4) and (1, 2)

The points that trisect the given points are P and Q with coordinates (p, -2) and (5/3, q) respectively

Therefore, we have;

The first point of the trisection cuts 1/3 of the length from one point and the second point of the trisection cuts 2/3 of the length from the same point

The coordinates of P or Q = (3 - (3 - 1)/3, -4 - (-4 - 2)/3) = (7/3 , -2)

Therefore, given that the y-coordinate value of the derived point coincides with the y-coordinate value of the point P, (p, -2) and there is only one point with x = -2 on the line, we have that the coordinate of the point P is (p, -2) = (7/3 , -2)

∴ P = 7/3

Similarly we have the second point of the trisection, Q, given as follows;

We are already given the x-coordinate value of the point Q as the 5/3 in (5/3, q)

Point Q = (5/3, q) = (3 - 2×(3 - 1)/3, -4 - 2×(-4 - 2)/3) = (5/3 , 0)

Point Q = (5/3, q) = (5/3 , 0)

∴ q = 0.

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3 years ago
The flaplike lateral wall of each atrium is called the
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You mean like the tricuspid and mitral (bicuspid) valves?
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Step-by-step explanation:

Using the values x=-2, y=4 and x=1, y=-5, the slope is \frac{-5-4}{1-(-2)}=-3.

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12/30 is simplified to 2/5 and<span>number of students trying out the same for both boys and girls</span> 16/40 is also simplified to 2/5 so YES the number of students trying out is the same for both boys and girls. I hope this helps :)
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3 years ago
How are rigid transformations used to justify the SAS congruence theorem?
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(Refer to the diagram in the attached photo.)

In this diagram there is defined two Sides and an Angle in between (SAS).

Notice how there are two loose endpoints in the diagram. A single line segment can be drawn connecting the endpoints, forming a unique triangle.

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