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Mnenie [13.5K]
3 years ago
8

What is an algebraic expression for “5 less than 9”

Mathematics
1 answer:
lakkis [162]3 years ago
8 0

Answer:  "less than" = subtract ( x - y )  

So in this case its is 5-9 = -4 or 9-5=4.

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Hey yall, 20 points? Factor to write an equivalent expression: 26a−10
Oksanka [162]

Answer:

2 (13a -5)

Step-by-step explanation:

Work Shown:

The GCF of 26 and 10 is 2. This is the largest factor that goes into both.

26a = 2*13a

10 = 2*5

So,

26a - 10 = 2*13a - 2*5 = 2(13a-5)

I'm using the distributive property to factor the 2 out.

7 0
3 years ago
Find the zero for f (x)=80-10x
kolbaska11 [484]

Answer: =80/11

Step-by-step explanation:x=80-10x

We move all terms to the left:

x-(80-10x)=0

We add all the numbers together, and all the variables

x-(-10x+80)=0

We get rid of parentheses

x+10x-80=0

We add all the numbers together, and all the variables

11x-80=0

We move all terms containing x to the left, all other terms to the right

11x=80

x=80/11

x=7+3/11

4 0
4 years ago
the temperature at 6 pm in frost frozen antarctica was -37 if the tem dropped 8 1 /2 c uring the next hour what was the the temp
Mice21 [21]

Answer:

-45 1/2

Step-by-step explanation:

4 0
3 years ago
Find the value of y.<br><br> 5<br> 8<br> 4<br> 2<br><br> 50 Pts!
Vinvika [58]

Answer and Explanation:

Since this is a 30-60-90 triangle, you can use the ratio of side lengths specific to this type of triangle:

x = 4√(2)

y = 2(4) = 8

because where 4 = T,

x = T√2    and     y = 2T

so again:

x = 4\sqrt{2}\\y = 8

8 0
3 years ago
Read 2 more answers
An account grows at an annual interest rate of r⁡​ ⁣, so it grows by a factor of x=1+r⁡​ ⁣⁣ ​⁡ each year. The function A(x)=800x
Paladinen [302]

Given:

Annual interest rate = r⁡​%

Growth factor : x = 1 + r⁡​

The below function gives the amount in the account after 4 years when the growth factor is x⁡​ ⁣⁣.

A(x)=800x^4+350x^3+500x^2+600x

To find:

The total amount in the account if the interest rate for the account is 3% each year and initial amount.

Solution:

Rate of interest = 3% = 0.03

Growth factor : x = 1 + ⁡0.03 = 1.03

We have,

A(x)=800x^4+350x^3+500x^2+600x

Substitute x=1.03 in the given function, to find the total amount in the account if the interest rate for the account is 3% each year.

A(1.03)=800(1.03)^4+350(1.03)^3+500(1.03)^2+600(1.03)

A(1.03)=800(1.12550881)+350(1.092727)+500(1.0609&#10;)+618

A(1.03)=900.407048+382.45445+530.45+618

A(1.03)=2431.311498&#10;

A(1.03)\approx 2431.31&#10;

Therefore, the total amount in the account is 2431.31 if the interest rate for the account is 3% each year.

For initial amount the rate of interest is 0.

Growth factor : x = 1 + ⁡0 = 1

Substitute x=0 in the given function to find the initial amount.

A(1)=800(1)^4+350(1)^3+500(1)^2+600(1)

A(1)=800+350+500+600

A(1)=2250

Therefore, 2250 was put into the account at the beginning.

3 0
3 years ago
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