Area of square = l²
Perimeter of square = 4l
According to the question,

Using zero product property,
Either,

Or,

Since length can't be negative,
the length is 9
J + 3 + 2j ≤ 18
3j + 3 ≤ 18
3j ≤ 15
j ≤ 5
jimmy's age is 5 years or less
Answer:

Step-by-step explanation:
So the first step is to add like terms since you can simplify the numerator by adding the two values sine they have the same variable and degree.
Add like terms:
![[\frac{8x^9}{2x}]^5](https://tex.z-dn.net/?f=%5B%5Cfrac%7B8x%5E9%7D%7B2x%7D%5D%5E5)
Divide by 2x (divide coefficient by 2, subtract coefficient degrees)
![[4x^8]^5](https://tex.z-dn.net/?f=%5B4x%5E8%5D%5E5)
Multiply exponents and raise 4 to the power of 5

The reason you multiply exponents is because you can think about it like this:
(4 * x * x * x * x * x * x * x * x) (this has one 4 and 8 x's because x is raised to the power of 8. Now if you do that 5 times which is what the exponent is doing you're going to have 40 x's and 8 4's. So it's essentially
(4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x). If you group like terms you'll get (4 * 4 * 4 * 4 * 4) * (x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x). Which simplifies to 4^5 * x ^ (8 * 5) which further simplifies to the answer 1024x^40
Answer:
2411.52 cm³
Step-by-step explanation:
V = (2/3)πr³ Use the equation for volume of a hemisphere
V = (2/3)(3.14)(8)³ Simplify the exponent
V = (2/3)(3.14)(512) Multiply
V = 1071.79 cm³
V = πr² h/3 Now find the volume of the cone
V = (3.14)(8)²(20/3) Simplify the exponent
V = (3.14)(64)(20/3) Multiply
V = 1339.73 cm³
Add both of the volumes together to get the volume of the figure.
1071.79 + 1339.73 = 2411.52 cm³
If this answer is correct, please make me Brainliest!
Answer:
∠1=160° and ∠2=20°
Step-by-step explanation:
Let ∠1 = x
∠2 = y
as these two angles are supplementary their sum is 180
that x+y=180 ----(A)
Also given that ∠1 is 20 degree less than nine times the size of ∠2.
Hence
x=9y-20
putting value of x in A and solving for y
9y-20+y=180
10y=180+20
10y=200
y=10
Putting this y in A
x+10=180
x=160