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3 years ago

15

I need help with linear functions can anybody help me?

1 answer:

NNADVOKAT [17]3 years ago

7 0

I can help you! Just let me how what the questions are

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Which ratio is equivalent to 3/15

Rzqust [24]

Answer:

Step-by-step explanation:

The ratio of 6:30 would be equivalent to it.

4 0

3 years ago

A + (-1.6 = -3.7 PLEASE I REALLY NEED HELP WITH THIS

raketka [301]

Answer:

yes ill help

Step-by-step explanation:

4 0

3 years ago

7. A business begins with $1,000,000 from its owners. It places $100,000 into a bank account which it wishes to maintain as a ca

joja [24]

Answer:

The amount need to borrow a owner is $100,000

Step-by-step explanation:

The total amount a owner having to start a business = $1,000,000.

He wishes to place $ 100,000 into bank account to maintain as cash reserve.

Now the amount he left with to spent in business purposes = $1,000,000 - $100,000 = $ 900,000.

He needs to purchase equipment and material of $1,000,000

But he is left with only $900,000.

So the amount he has to borrow to fulfill his business requirement is

= $1,000,000 - $900,000 = $100,000

8 0

3 years ago

Determine whether or not the vector field is conservative. If it is conservative, find a function f such that F = ∇f. (If the ve

djyliett [7]

We're looking for $f(x,y,z)$ such that $\nabla f(x,y,z)=\vec F(x,y,z)$ , which requires

$\dfrac{\partial f}{\partial x}=xyz^2$

$\dfrac{\partial f}{\partial y}=x^9yz^2$

$\dfrac{\partial f}{\partial z}=x^9y^2z$

Integrating both sides of the first PDE wrt $x$ gives

$f(x,y,z)=\dfrac12x^2yz^2+g(y,z)$

Differenting this wrt $y$ gives

$\dfrac{\partial f}{\partial y}=x^9yz^2=\dfrac12x^2z^2+\dfrac{\partial g}{\partial y}$

$\implies\dfrac{\partial g}{\partial y}=\dfrac12x^2z^2(2x^7y-1)$

but we're assuming $g(y,z)$ is a function that doesn't depend on $x$ , which is contradicted by this result, and so there is no such $f$ and $\vec F$ is not conservative.

8 0

4 years ago

Algebra 2: PLEASE HELP ME!!

vfiekz [6]

Looks more like Trig than Algebra II

They want us to apply the sum angle formula to $\sin(x + \frac{5 \pi}{6})$

5π/6 is 150°; I find it easier to think in degrees.

When the tangent of x is 3/4 that's a right triangle with opposite 3, adjacent 4 so hypotenuse 5. So a sine of 3/5 and a cosine of 4/5, both positive because we're told x is in the first quadrant.

The sine sum angle formula is

$\sin(a+b) = \sin a \cos b + \cos a \sin b$

$\sin(x+\frac{5\pi}{6}) = \sin x \cos \frac{5\pi}{6} + \cos x \sin \frac{5\pi}{6}$

We know sin 150° = sin 30° = 1/2 and cos 150° = - cos 30° = -√3/2

$\sin(x+\frac{5\pi}{6}) = \frac 3 5 (- \sqrt{3}/2) + \frac 4 5 (1/2)$

$\sin(x+\frac{5\pi}{6}) = \dfrac{ 4- 3\sqrt{3}}{10}$

Third choice

3 0

3 years ago