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Nezavi [6.7K]
3 years ago
14

Technician A says that water floats to the top of fuel in the tank. Technician B says that water is more likely to be drawn into

the system when the fuel level is low. Which technician is correct?
Chemistry
1 answer:
svet-max [94.6K]3 years ago
4 0

Answer:

Of course, technician B is the smarter one!    

                           

Explanation:

Water molecules attract each other, and the oil molecules also stick together. That causes oil and water to form two separate layers.

Because water molecules are denser than oil, they sink to the bottom, leaving oil sitting on top of the water.

Now, many fuel systems are designed in such a way that the suction pipe is located at the base of the tank. Given the above, it is very easy to see why water to a great degree of probability will be drawn into the system when the fuel level is low.

Cheers!

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Choose the pair of substances that are most likely to form a homogeneous solution.
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Answer is: <span>a. c6h14 and c10h20.
This pair will </span>most likely form a homogeneous solution because they are both nonpolar substances and "li<span>ke dissolves like".
Other pairs will not form homogeneous solution because nonpolar substances have low solubility in polar or ionic substances (for example LiBr is ionic and C</span>₅H₁₂ is nonpolar).
7 0
3 years ago
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A chemist prepares a sample of helium gas at a certain pressure, temperature and volume and then removes all but a fourth of the
cupoosta [38]

Answer:

The temperature must be changed to 4 times of the initial temperature so as to keep the pressure and the volume the same.

Explanation:

Pressure in the container is P and volume is V.

Temperature of the helium gas molecules =T_1

Molecules helium gas = x

Moles of helium has = n_1= \frac{x}{N_A}

PV = nRT (Ideal gas equation)

PV=n_1RT_1...[1]  

After removal of helium gas only a fourth of the gas molecules remains and pressure in the container and volume should remain same.

Molecules of helium left after removal = \frac{x}{4}

Moles of helium has left after removal = n_2= \frac{x}{4\times N_A}

PV=n_2RT_2...[2]

n_1RT_1=n_2RT_2

\frac{x}{N_A}\times T_1=\frac{x}{4\times N_A}\times T_2

T_1=\frac{T_2}{4}

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The temperature must be changed to 4 times of the initial temperature so as to keep the pressure and the volume the same.

6 0
3 years ago
A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4
san4es73 [151]

Answer:

83.20 g of Na3PO4

Explanation:

1 mole of Na3PO4 contains 3 moles of Na+.

Mole of Na ion to be prepared = Molarity x volume

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If 1 mole of Na3PO4 contains 3 moles of Na ion, then 0.5075 Na ion will be contained in:

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mole of Na3PO4 = mass/molar mass = 0.1692

Hence, mass of Na3PO4 = 0.1692 x molar mass

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                                        = 83.20 g.

83.20 g of Na3PO4 will be needed.

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Answer:

i believe it is strong acids, strong bases, and salts.

Explanation:

Hope this helps : )

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