A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4

Question

3 years ago

9

will be needed to produce 725 mL of a solution that has a concentration of Na ions of 0.700 M

2 answers:

SOVA2 [1] · Answer 1 · 2022-01-20T20:33:35+03:00

SOVA2 [1]3 years ago

6 0

Explanation:

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san4es73 [151] · Answer 2 · 2022-01-20T19:06:35+03:00

Answer:

83.20 g of Na3PO4

Explanation:

1 mole of Na3PO4 contains 3 moles of Na+.

Mole of Na ion to be prepared = Molarity x volume

= 0.700 x 725/1000

= 0.5075 mole

If 1 mole of Na3PO4 contains 3 moles of Na ion, then 0.5075 Na ion will be contained in:

0.5075/3 x 1 = 0.1692 mole of Na3PO4

mole of Na3PO4 = mass/molar mass = 0.1692

Hence, mass of Na3PO4 = 0.1692 x molar mass

= 0.1692 x 163.94

= 83.20 g.

83.20 g of Na3PO4 will be needed.