Answer: 2 moles
Explanation:
STP is Standard Temperature and Pressure. That means the pressure is 1.00 atm and the temperature is 273K. Since the oxygen is placed in the same container, we can use Ideal Gas Law to figure out what container the CO₂ used.
Ideal Gas Law: PV=nRT
P=1.00 atm
n=moles
R=0.08206 Latm/Kmol
T=273K
CO₂



Since we know that CO₂ has a 44.8 L container, we can use that to find the moles of oxygen.



There are 2 mol of oxygen.
Answer:
D and R are in the same period
Explanation:
remember groups are vertical and periods are horizontal!
Answer:
variable: not consistent or having a fixed pattern; liable to change.
Explanation:
Aldehyde is a group of organic compounds with the general form of RCHO. Oxidation of aldehyde can lead to the formation of the carboxylic acids, with the general form of RCO₂H.
With this oxidation, the typical reagents promoting the oxidation are chromic acids, chromate salts, permanganate, etc.