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fenix001 [56]
4 years ago
10

You must exert a force of 5N on a book to slide it across a table.If you do 2.5 J of work in the process, how far has the book m

oved?

Physics
1 answer:
I am Lyosha [343]4 years ago
3 0

Answer:

0.5 m.

Explanation:

From the question given above, the following data were obtained:

Force (F) = 5 N

Work done (W) = 2.5 J

Distance (s) =?

Workdone is simply defined as the product of force (F) and distance (s) moved in the direction of the force. Mathematically, it is expressed as:

Work done (W) = Force (F) × Distance (s)

W = F × s

With the above formula, we can obtain the distance to which the book has moved as follow:

Force (F) = 5 N

Work done (W) = 2.5 J

Distance (s) =?

W = F × s

2.5 = 5 × s

Divide both side by 5

s = 2.5/5

s = 0.5 m

Therefore, the book moved 0.5 m when the force was applied.

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What is the value of acceleration due to gravity, g, on Earth?
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It varies with altitude, but at sea level, it's 9.8 m/s².

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2. Which of the following cell structures is the site of photosynthesis?
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Option C. The chloroplasts contain chlorophyll pigments requires for photosynthesis.

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3 years ago
Challenge question: An arrow is placed at 3 centimeters to the left of a converging lens. The image appears at 3 centimeters to
Zanzabum

The focal length of the converging lens based on the arrow placed  3 centimeters to the left and the imaged formed 3 cm to the right is 1.5 cm.

<h3>Focal length of the converging lens</h3>

The focal length of the converging lens is determined by applying the following converging lens formula.

1/f = 1/v + 1/u

where;

  • v is the image distance = 3 cm
  • u is the object distance = 3 cm
  • f is the focal length = ?

1/f = 1/3 + 1/3

1/f = 2/3

f = 3/2

f = 1.5 cm

Thus, the focal length of the converging lens is 1.5 cm.

Learn more about converging lens here: brainly.com/question/22394546

8 0
2 years ago
An object starts from rest and has an acceleration given by a = 3.00 t^2 – 4.20 t. Determine how far the object is from its star
Korolek [52]

Answer:

38.7 units

Explanation:

a = 3.00 t² – 4.20 t

Integrate to find velocity as a function of time.

v = ∫ a dt

v = ∫ (3.00 t² – 4.20 t) dt

v = 1.00 t³ – 2.10 t² + C

The object starts at rest, so at t = 0, v = 0.

0 = 1.00 (0)³ – 2.10 (0)² + C

0 = C

v = 1.00 t³ – 2.10 t²

Integrate to get position as a function of time.

x = ∫ v dt

x = ∫ (1.00 t³ – 2.10 t²) dt

x = 0.250 t⁴ – 0.700 t³ + C

Find the difference in positions between t = 4.50 and t = 0.

Δx = [0.250 (4.50)⁴ – 0.700 (4.50)³ + C] – [0.250 (0)⁴ – 0.700 (0)³ + C]

Δx = 0.250 (4.50)⁴ – 0.700 (4.50)³

Δx = 38.7

The object moves 38.7 units.

7 0
3 years ago
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