Answer:
300 N
Explanation:
The net force acting on the arrow is given by Newton's Second Law:
where
m = 0.06 kg is the mass of the arrow
a = 5,000 m/s^2 is the acceleration of the arrow
Substituting the numbers into the equation, we find
Challenge question: An arrow is placed at 3 centimeters to the left of a converging lens. The image appears at 3 centimeters to
1 answer:
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The fundamental frequency of a string is given by:
where L is the string's length, T the tension and
the linear density of the string.
We can see that f1 is proportional to the square root of T:
.
This means that if the new tension is half the initial value, the new fundamental frequency will be proportional to
So, the new fundamental frequency will be
where L is the string's length, T the tension and
We can see that f1 is proportional to the square root of T:
This means that if the new tension is half the initial value, the new fundamental frequency will be proportional to
So, the new fundamental frequency will be
Answer:
= 1.75 × 10⁻⁴ m/s
Explanation:
Given:
Density of copper, ρ = 8.93 g/cm³
mass, M = 63.5 g/mol
Radius of wire = 0.625 mm
Current, I = 3A
Area of the wire, =
Now,
The current density, J is given as
= 2444619.925 A/mm²
now, the electron density,
where,
=Avogadro's Number
Now,
the drift velocity,
where,
e = charge on electron = 1.6 × 10⁻¹⁹ C
thus,
= 1.75 × 10⁻⁴ m/s