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alekssr [168]
3 years ago
7

Which type of arrow is being shown if viewing a physics diagram and there is a soccer ball on the grass with an arrow that shows

BOTH the speed and direction of the ball?
an acceleration arrow


1. a vector

2. a force arrow

3. a speed arrow
Please Answer and thank you.
Physics
1 answer:
Nady [450]3 years ago
7 0

Answer:

it is a vector arrow

a vector show the speed and direction

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Dennis_Churaev [7]

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8 0
4 years ago
An airplane is flying in air with a density of 1.29 kg/m3. A pressure gauge measures
jeka57 [31]

Answer:

341 m/s

Explanation:

Use Bernoulli equation:

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

Assuming no elevation change, h₁ = h₂.

P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²

The velocity of the air at the nose is 0 m/s, so:

P₁ = P₂ + ½ ρ v₂²

ΔP = ½ ρ v₂²

Plugging in values:

75000 Pa = ½ (1.29 kg/m³) v²

v = 341 m/s

5 0
3 years ago
What is the speed of a proton whose kinetic energy is 3.4 kev ?
Andreas93 [3]
The kinetic energy of the proton is 3.4 kev
1 kev = 1.602 × 10^-16 joules
therefore 3.4 kev is equivalent to;
3.4 ×  (1.602 ×10^-16)= 5.4468 × 10^-16 J
Kinetic energy is calculated by the formula 1/2mv² where m is the mass and v is the velocity.
Therefore V = √((2 × ( 5.4468×10^-16))/ (1.67 ×10^-27))
                    = 8.077 × 10^5 m/s

8 0
4 years ago
Suppose that a spiral galaxy is located at the center of a spherically symmetric dark matter halo
Novosadov [1.4K]

To solve the problem it is necessary to use the concepts of Orbital Speed considering its density, and its angular displacement.

In general terms the Orbital speed is described as,

V_{orbit} = \sqrt{\frac{G\rho 4\pi r^3}{3}}

PART A) If the orbital speed of a star in this galaxy is constant at any radius, then,

\frac{4\pi G\rho r}{3} = \frac{v^2}{r}

\frac{4\pi G\rho r}{1} = \frac{3v^2}{r}

\frac{\rho}{1} = \frac{3v^2}{r^2 4\pi G}

\rho = \frac{1}{r^2}

PART B) This time we havev=\omega t, where \omega is the angular velocity (constant at this case)

\frac{4\pi G\rho r}{3} = \frac{v^2}{r}

\frac{4\pi G\rho r}{3} = \frac{(\omega r)^2}{r}

\rho = \frac{3\omega r}{4\pi Gr}

\rho = \frac{3\omega^2}{4\pi G} \propto constant

PART C) If the total mass interior to any radius r is a constant,

\frac{4\pi G\rho r}{3} = \frac{v^2}{r}

\frac{GM}{r^2}=\frac{v^2}{r}

v = \sqrt{\frac{GM}{r}}

v= \sqrt{\frac{1}{r}}

3 0
4 years ago
You are a psychic when you tap into your other__% of your brain.
vladimir1956 [14]
20% would be probably right cuz 100% is total and 80+ what gives u 100 which is 20
4 0
3 years ago
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