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Lady_Fox [76]
3 years ago
5

Please help meeee it’s important

Mathematics
2 answers:
NARA [144]3 years ago
5 0

Answer:

um what do u need

Step-by-step explanation:

Talja [164]3 years ago
3 0

Answer:what is your problem that’s you need help in

Step-by-step explanation:

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An item on sale costs 10% of the original price. The original price was $69 . Wats the price now
9966 [12]

Answer:

$62.10

Step-by-step explanation:

The difference is $6.90

Hope this helps.

4 0
3 years ago
Read 2 more answers
13)
Law Incorporation [45]

The Domain (x-values and independent variable) would be the time of day

The Range (y-values and dependent variable) would be the amount of people in a movie theater

5 0
2 years ago
Need help. asap. also need an explanation for the problem. :)
Maurinko [17]

Answer:

124858

Step-by-step explanation:

The first 4 digits are simple, you multiply the first digit of the equation by the 2nd digit and then for the other 2 you multiply the first digit of the equation by the 3rd digit.

6 + 2 + 8

6 * 2 = 12

6 * 8 = 48

Then the last 2 digits are the sum of the products of the 1 and 2 and 1 and 3 and subtract it by the 2

12 + 48 = 60

60 - 2 = 58

Put them together

7 0
2 years ago
50 points! I understand A. and B. but I would really appreciate help with C.
FromTheMoon [43]

Answer:

51.72\text{ cells per hour}

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

P(t)=6.10t^2-9.28t+16.43

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]

Expand:

P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]

Differentiate. Use the power rule:

P'(t)=6.10(2t)-9.28(1)

Simplify:

P'(t)=12.20t-9.28

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

P'(5)=12.20(5)-9.28

Multiply:

P'(5)=61-9.28

Subtract:

P'(5)=51.72

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0
2 years ago
Which statements best describe displacement? Check all that apply.
natima [27]
I think it’s how far an object travels from starting point to ending point.
7 0
3 years ago
Read 2 more answers
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