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2 years ago

12

Suppose x is any positive number. Circle 1: center (0, 0) and radius 2x Circle 2: center (0, 0) and radius 10x Why is circle 1 s

imilar to circle 2?

1 answer:

Alexeev081 [22]2 years ago

3 0

Answer:

Because both have the center of (0,0)

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Suppose you had D dollars in your bank account. you spent $22 but have at least $28 left. how much money did you have initially?

nalin [4]

Answer:

Answer:

d--22→ 28

d→ 50

Step-by-step explanation:

Let d dollars be the initial amount in your bank account.

We have been given that you spent $22, so the amount left after spending $22 will be: .

We are also told that after spending $22, you have at least $28. This means that the amount left after spending $22 will be greater than or equal to $28.

We can represent this information in an equation as:

Therefore, the inequality represents the initial amount of money you had.

Now let us solve for d by adding 22 to both sides of our inequality.

Therefore, initially you had at least $50.

Still stuck? Get 1-on-1 help from an expert tutor now.

Step-by-step explanation:

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8 0

2 years ago

What is the value of f(-4)

WITCHER [35]

Answer:

7

Step-by-step explanation:

Substitute x = -4 :

f(-4) = 3 - (-4)

= 3 + 4

= 7

4 0

2 years ago

What is the product of (a+b) (a-b)

VashaNatasha [74]

Answer:

$a^{2}+b^{2}$

Step-by-step explanation:

(a+b)(a-b)

$a^{2}$ -ab+ab- $b^{2}$

$a^{2} + b^{2}$

5 0

2 years ago

Find the inverse of the function f(x) = (x - 4) 2 - 5 if x ≥ 4.

Serggg [28]

Same here, we do a quick switcharoo on the variables first,

$\bf \stackrel{f(x)}{y}=(x-4)^2-5\qquad inverse\implies \boxed{x}=\left( \boxed{y}-4 \right)^2-5
\\\\\\
x+5=(y-4)^2\implies \pm\sqrt{x+5}=y-4\implies \pm\sqrt{x+5}+4=y$

6 0

2 years ago

1. The coordinates of the vertices of parallelogram RMBS are R(–4, 5), M(1, 4), B(2, –1), and S(–3, 0). Using the diagonals, pro

Whitepunk [10]

First, plot the points. Point R would be somewhere in the second Quadrant, point M would be in the first quadrant 1, point B would be in the fourth quadrant, and point S would be on the negative y-axis. A property of rhombi is that their diagonals are perpendicular. One would need to calculate the slopes of the diagonals and determine whether or not they are perpendicular. Lines are perpendicular if and only if their slopes are opposite reciprocals. Example: 2 and -0.5
Formulas needed:
Slope formula:
$\frac{ y_{2}- y_{1} }{ x_{2} - x_{1} }$

The figure would look kinda like this:
R
M

S
B
Diagonals are segment RB and segment SM
So, your slope equations would look like this:
$\frac{-1-5}{2-(-4)}$
and
$\frac{4-(-3)}{1-0}$
Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram

7 0

2 years ago