Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
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Answer:
The coordinates of P' are (4.8,-4.8).
Step-by-step explanation:
The rule of dilation 
represent the dilation with scale factor 2.4 and center at origin.
If the scale factor of the dilation is k and the center is (0,0), then
Since the scale factor is 2.4, therefore
From the given figure it is noticed that the coordinates of P are (2,-2). The coordinates of P' are
Therefore the coordinates of P' are (4.8,-4.8).
Answer:
x = 7
3x + 11 = 32
8x + 2 = 58
Step-by-step explanation:
3x + 11 + 8x + 2 = 90
11x + 13 = 90
11x = 77
x = 7
3x + 11 = 3(7) + 11 = 32
8x + 2 = 8(7) + 2 = 58
